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What is the balanced chemical equation for the double replacement of H2C2O4 KOH?


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Answered 2011-12-04 23:24:12

It's a neutralization reaction.

H2C2O4 + 2KOH -> 2H2O + K2C2O4

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What is the balanced equation for H2C2O4


Oxalic acid + Sodium Hydroxide ----> Sodium Oxalate + WaterH2C2O4 + 2 NaOH ----> Na2C2O4 + 2 H2O



H2C2O4, It is HOOC-COOH


H2C2O4 + 2KOH --> K2C2O4 + 2H2O


I have no clue but I do know that your wife is going out with 26 other men


H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l) H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l)


2NaOH + H2C2O4 → Na2C2O4 + 2H2O



The name of the compound H2C2O4 is oxalic acid.


The name of the compound H2C2O4 is oxalic acid.



Oxalic acid has the chemical formula H2C2O4. It is a strong dicarboxylic acid occurring in many plants and vegetables.


Well, when I looked online for the formula for oxalic acid, it said it was H2C2O4. If this is correct the equation would be H2C2O4 + Al(OH)3 --> H2O..... Something... Im not sure about that last part because the oxalic acid formula doesnt seem right to me... But it would be a double-displacement reaction.


The word equation for rust iz = Iron+oxygen+water Vapour oxalic acid (removing agent) h2c2o4 Fe2O3 + 6H2C2O4 -> 2Fe(C2O4)3{-3} + 3H2O + 6H {+1} Hope that helps!


oxalic acid- joana cel


It depends on its concentration in water


Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity


0.063 g of oxalic acid * (1 mol H2C204*2H2O / 126.07 g) = 0.0004997 mol H2C2O4*2H2O 0.0004997 mol H2C204 / 0.250 L = 0.001999 M of H2C2O4


Oxalic acid has covalent bonds.




There are many acids with many different chemical formulas. Here are a few common ones: Sulfuric acid: H2SO4 Acetic acid: CH3CO2 Carbonic acid: H2CO3 Hydrochloric acid: HCl Oxalic acid: H2C2O4 Nitric acid: HNO3


It is not important whether this '200 ml of solution' is countable without or without the hydrated compounds contribution of H2C2O4.2H2OAt first find moles of this3.78 grams H2C2O4 . 2H2O ( 1 mole cpd./126.068 grams)= 0.02998 moles H2C2O4 . 2H2OSince Molarity = moles of solute/Liters of solution ( 200 ml = 0.200 Liters )Molarity = 0.02998 moles H2C2O4 . 2H2O/0.200 Liters= 0.150 M H2C2O4.2H2O


The conjugate acid of HC2O4- is oxalic acid, H2C2O4.



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