Write a balanced chemical equation for the synthesis of liquid water from its elements?

Answer 1

O2(g) +2H2(g)->2H2O(g)

Oxygen and Hydrogen in their most common forms are both gaseous. when combined together and burned in a combustion reaction (lighting hydrogen on fire in the presence of O2) gaseous H2O is formed, more commonly known as steam. to balance the equation you have to recognize the ratio between the two elements in your product, hydrogen and oxygen are at a 2:1 ratio. Also you must know that they are both diatomic gasses (two oxygen or hydrogen atoms to one molecule of oxygen or hydrogen) with this infromation you can make a basic equation of

O2(g)+H2(g)->H2O

this is unbalanced, because the products have one oxygen and the reactants have two oxygen atoms. to fix this we will make two water molecules giving us the equation:

O2(g)+H2(g)->2H2O

Now we have 4 hydrogen on the products side and only 2 atoms of hydrogen on the products side, to balance add another MOLECULE of hydrogen, giving two hydrogens to balance the equation, giving us the final equation of

O2(g) +2H2(g)->2H2O(g)

Answer 2

2No2 + 7H2 --------------------> 2NH3+4H2O

Answer 3

The balanced equation for the formation of water is

2H2(g) + O2(g) --> 2H2O(l)

Answer 4

H2(g) + O(g) => H20(l)

Answer 5

2h2 + o2 -------> 2h2o