2(c3h8o)+9o2 => 8h2o+6co2
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
that is the equation for burning popane
This is the chemical reaction for burning of propane.
First of all you have to determine the equation for the reaction: C3H8 + 5 O2 -----> 3CO2 + 4H2O Now we determine the limiting reactant: C3H8= (12*3) + (8*1)=44g/mol 8g C3H8 * (1mol/44g ) * (5 O2 / 1 C3H8) * (32g/1mol O2) = 29.09 g O2 So, 8g of C3H8 would use up 29.09 grams of O2 in order for this reaction to go to compleation. Since we have only 8 g of O2, O2 will run out first. So, it is considered the limiting reactant. In the next step we use the same method to determine mass of CO2 formed: 8g O2 * (1mol O2 /32g) * (3CO2 / 5 O2) * (44g/1mol CO2) = 6.6 g CO2 if you have any more questions feel free to e-mail me on micuninikola@yahoo.com I ll be glad to help out Nick Nikolic, Chemistry 121 student
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A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O (g) is the chemical equation for the combustion of propane.
Study island answer: C3H8 + 5O2 3CO2 + 4H2O
Propane ( C3H8 ) Will burn completely in excess oxygen to form water and carbon dioxide;C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
The chemical reaction is: C3H8 + 5 O2 = 3 CO2 + 4 H2O
that is the equation for burning popane
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
C3h8+ 5o2---> 3co2+ 4h2o
This answer represents a balanced chemical equation for the combustion of propane (C3H8). When propane reacts with oxygen (O2), it produces carbon dioxide (CO2) and water (H2O).
I believe you put in the wrong equation. This equation cannot be solved.
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED