The formula is Fe(CN)2. Iron(II) has 2 valence electrons, and bonds ionically with the cyanide polyatomic ion, which carries a -1 charge.
This is an ionic compound NOT a covalent compound
Formula: Fe(CN)2
Fe3[Fe(CN)6]2.
Fe (CN)3
FeCN_2_
Fe(SCN)2
Sn(cn)2
Tin (II) cyanide has the formula Sn(CN)2.
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.
The chemical formula for Tin(II) Bromide is SnBr2.
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
TiS for titanium sulfide (titanium(II) sulfide) and TiS2 for titanium disulfide (titanium(IV) sulfide)
Tin (II) cyanide has the formula Sn(CN)2.
THere is a compound tin(II) cyanide- (stannous cyanide) - Sn(CN)2- there does not appear to be a stannic that I can find which would be Sn(CN)4
The chemical formula for tin sulphide is SnS
The chemical formula for tin (IV) sulfide is SnS2.The chemical formula for tin (II) sulfide is SnS.
SnSO3
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
Tin(II) sulfide is a chemical compound of tin and sulfur. Its chemical formula is SnS.
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.
The formula is Sn3(PO4)2.
The chemical formula for Tin(II) Bromide is SnBr2.
Tin has two oxidation states (II and IV), and exhibits approximately equal stability in both its II and IV oxidation state. The chemical formula Tin (II) Iodide is SnI2. The chemical formula for Tin (IV) Iodide is SnI4.
Sn(OH)2