Thallium is an element on the Periodic Table. It's atomic number is 81.
Because it is an element, I don't understand what you mean by "its formula".
The symbol for Thallium is Tl, so the formula would be Tl...
If you want the formula for a compound with thallium, that's a different story.
It is not a diatomic element, if that's what you meant.
For more information on thallium, go to
http://en.wikipedia.org/wiki/Thallium
Thallium(I) chloride Molecular formula is TlCl. Your Welcome
Formula: TlOH
Formula: Tl2C2O4
Th
Tl2S3
The chemical formula of gold(III) sulfide is Au2S3.
n2s3
Co2S3 is the formula for cobalt (III) sulfide.
Chromium III is Cr3+. The roman numeral tells you the charge. Sulfide is S2-. You can figure this out from the periodic table. Sulfur needs two electrons to be like Argon, the next noble gas. When they form a compound, they combine in a ratio such that the total positive charge balances the total negative charge. 2 Cr3+ ions have a total charge of +6. 3 S2- ions have a total charge of -6. So the formula is Cr2S3.
These are the ions and their charges: Fe+3 SO3-2The charges have to add up to zero, so two +3 iron ions cancel out three -2 sulfite:Fe+3 Fe+3 SO3-2 SO3-2 SO3-2Simplify: Fe2(SO3)3
Thallium(III) nitrate is Tl(NO3)3. Thallium(I) nitrate is TlNO3.
The chemical formula of gold(III) sulfide is Au2S3.
n2s3
Co2S3 is the formula for cobalt (III) sulfide.
Ni2S3
Cobalt (III) Sulfide
The formula of iron (III) sulfide is Fe2S3, showing that each formula unit contains two iron atoms. The gram formula unit mass for iron (III) sulfide is 207.87, and the gram atomic mass of iron is 55.847. Therefore, the fraction by mass of iron in iron (III) sulfide is 2(55.847)/207.87 or about 0.5373, and the grams of iron in 130 g of iron (III) sulfide is 0.5373 X 130 or 69.9 grams, to the justified number of significant digits.
divanadiumtrisulfide
Ferrous Sulfide = Iron (III) Sulfide Both -> Fe2S3
The two main oxidation states of thallium are +1 and +3. In the oxidation state +1 most compounds closely resemble the potassium or the silver compounds (The ionic radius of thallium(I) is 1.47 Å while that of potassium is 1.33 Å and that of silver is 1.26 Å). For example, the water-soluble and very basic thallium(I) hydroxide reacts with carbon dioxide forming water-soluble thallium carbonate This carbonate is the only water soluble heavy metal carbonate. The similarity with silver compounds is observed with the halide, oxide, and sulfide compounds. Thallium(I) bromide is a photosensitive yellow compound very similar to the silver bromide, while the black thallium(I) oxide and thallium(I) sulfide are very similar to the silver oxide and silver sulfide. The compounds with oxidation state +3 resemble the aluminium(III) compounds. They are moderately strong oxidizing agents, as illustrated by the reduction potential of +0.72 volts for Tl3+ + 3 e- → Tl(s). The thallium(III) oxide is a black solid which decomposes above 800 °C, forming the thallium(I) oxide and oxygen.[4]
This compound is thallium(III) hydroxide.
Chromium III is Cr3+. The roman numeral tells you the charge. Sulfide is S2-. You can figure this out from the periodic table. Sulfur needs two electrons to be like Argon, the next noble gas. When they form a compound, they combine in a ratio such that the total positive charge balances the total negative charge. 2 Cr3+ ions have a total charge of +6. 3 S2- ions have a total charge of -6. So the formula is Cr2S3.