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Balanced equation.

KOH + HBr -> KBr + H2O

everything is one to one, so...

Molarity = moles of solute/liters of solution ( change ml to liters )

0.25 M KOH = moles KOH/0.015 liters

= 0.00375 moles of KOH

this is as many moles that you have of HBr, so...

Molarity of HBr = 0.00375 moles/0.012 liters

= a concentration of HBr that is 0.31 M

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13y ago
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Q: What is the concentration of a HBr solution in 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
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