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What is the cos of angle a 5 13 12?

Updated: 4/28/2022
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9y ago

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It is: cos = adj/hyp and the acute angles for the given right angle triangle are 67.38 degrees and 22.62 degrees

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Q: What is the cos of angle a 5 13 12?
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What is the cos of angle a if the opposite is 5 the adjacent is 12 and the hypotenuse is 13?

It is: cos^-1(12/13) = 22.61986495 degrees


What is the cos of angle 'a' with the measurements 5 13 12?

The answer depends on which of the three angles 'a' is!


What is cos of angle a with a hypotenuse of 13 and adjacent of 5 and a opposite of 12?

It is about 67 degrees


What is the exact ratio of all 6 trig functions when p is a point on a circle at 5 -12?

sin = -12/13 cos = 5/12 tan = -5/12 cosec = -13/12 sec = 12/5 cotan = -12/5


What is the sin of angle A 5 13 12?

The dimensions given fits that of a right angle triangle and sin^-1(12/13) = 67.38 degrees


What is the sin of angle a if bc is 5 ba is 13 and ca is 12?

5/13 = 0.3846 (to 4 dp)


Does 51213 form a right angle?

If you mean 5 by 12 by 13 then they will form a right angle triangle


How do you calculate cos squared theta equals one minus twelve thirteenths squared?

Writing x instead of theta, cos2x = 1 - (12/13)2 = 1 - 144/169 = 25/169 = (5/13)2 So cos(x) = ± 5/13 so that x = cos-1(5/13) or cos-1(-5/13) And then, depending on the range of x, you have solutions for x. A calculator will only give you the principal solutions, though.


What is the cos of angle A if the opposite is 3 and the adjacent is 4 and the hypotenuse is 5?

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What Angle A of triangle SAM is a right angle. If SM 13 mm and MA 12 mm determine the length of segment SA.?

If the right angle is at A then SA = 5 mm.


Do 5 12 13 form a right angled triangle?

Yes they do for a triangle using Pythagorean theorem 5 squared + 12 squared = 13 squared


What is the measurement of angle B in the triangle when the hypotenuse is 13 the opposite side is 12 and the adjacent side is 5?

You have not indicated which side the angle is opposite of. Can us law of cosines then by calling sides c and a. b^2 = a^2 + c^2 - 2(a)(c) cos(B) I would arbitrarily have to assign values you have not given me.