cut in voltage *** for silicon is 0.7volts and that for germanium is 0.3volts.
According to Millman and Taub, "Pulse, Digital and Switching Waveforms", McGraw-Hill 1965, the cutin (or offset, break-point or threshold) voltage for a silicon diode is 0.6, and 0.2 for germanium.
Breakdown voltage is another thing entirely. It is the reverse voltage at which the junction will break down.
Potential barrier of silicon is 0.7, whereas potential barrier of germanium is 0.3
Cut-in voltage is the value of voltage at which appreciable current begins to flow when a pn junction is forward biased.
Silicon Ingot:A large, cylindrical, single crystal made from purified silicon. The cylinder is sliced into thin wafers which are used for making computer chips. Silicon Wafer:Intel uses wafers of pure silicon cut from a silicon ingot to make microprocessors. Silicon, the primary ingredient of beach sand, is a semiconductor of electricity. Semiconductors are materials that can be altered to be either a conductor or an insulator.
No, a diode can rectify an AC signal but is not able to amplify an AC signal. Diodes are two layer devices whereas transistors have three. It is this very thin 'base' region in the transistor that gives it the ability to give a voltage or current gain.
A transistor can be in three conditions or states. It can be active (at a voltage higher than the emitter), in saturation or cut off (no current).
It prevents the voltage spike that occurs when the magnetic lines of force cut across the solenoid windings when someone shuts the power off the solenoid. It is called inverse voltage and on a 12 volt coil, when you turn it off, the collapsing magnetic field can generate an inverse voltage of 200 volts or more for a split second. This is why sometimes you can get a "poke" out of a 12 volt system. It is the inverse voltage spike that causes a momentary shock to your fingers or body. (this momentary voltage is not harmful to a human). when a coil has a charge cause by applying DC and suddenly disconnected this charge will manifest as a voltage of opposite polarity across the coil the diode will clamp this charge to .6-.7 v removing reverse breakdown voltage present
silicon diodes Cut in voltage is 0.7 V.but the Germanium cut in voltage is 0.3 V that's why .............
for germanium it is 0.3 and for silicon it is 0.7
the valence band energy is different in the two substances,so the cut in voltage is different.
The cut in voltage is that voltage where after the current increase rapidly and it's value is different-2 for different type of semiconductor. for silicon it is 0.7 and for germanium it is 0.3 volt. It means if you made a diode from silicon than applied voltage below 0.7 volt will not able to flow current (if flow than it is in term of few micro ampere) . it means diode will stay in off mode and for germanium same things will happen and it will rest on off condition below 0.3 volt(applied).
The symbol 'A' indicates that this device is made from germanium . as you may know germanium has less cut in voltage so this device is used for low power signal or for signal processing. also the leakage current or reverse saturation current of germanium is greater than silicon.
It is not 'Cutting voltage' but it is Cut-in voltage'. It is the voltage at which the diode turns ON. For silicon it is 0.7v. After reaching 0.7V diode current starts increasing rapidly for little increase in voltage.
No,it is not possible to reduce or increase the cut in voltage of the diode after the manufacturing of the diode but we can design zener diodes of various values of cut in voltage.But it is able to do that only at the time of manufacturing
the cut in vol for silicon diode is 0.7 where as germaium is around 0.3 because of their construction( the ratio of majority n minority carreirs)
the cut in vol for silicon diode is 0.7 where as germaium is around 0.3 because of their construction( the ratio of majority n minority carreirs)
It's a diode that is used to limit a voltage to some desired value. Importantly, it's used to limit a transient voltage or an alternative voltage. The simplest example is that diode placed across a relay's inductive coil. As current is cut off through the coil, a large induced voltage appears that can cause damage to the circuit. A diode can be placed in circuit to catch/damp the induced voltage.
If you're looking for a definition, it's: the voltage at which, a diode can be considered a "short circuit" or low-value resistor It varies with each diode, but most have approximately 0.6 or 0.7 Volts across them when you get almost 1mA flowing FORWARD through them. For light emitting diodes (LEDs), it varies between diodes and is largely dependent on the colour of the light. Green ones typically have 1.3V @ 1mA, red = 1.8V @ 1mA, and higher for other colours. Infrared LEDs usually have 1.1V @ 1mA. Higher cutoff voltages occur at higher forward currents, meaning that at 1mA, Vf might be 1.8V for a certain diode, but at 10mA Vf is maybe 1.9V. One important side note is that reverse current is still possible, but is so small it's usually negligible. Also, it's not recommended to force current backwards through a diode (exception: Zener diodes) because it usually requires a higher voltage to accomplish this. The cutoff voltage of a diode is the maximum voltage that the diode can withstand in the revers biase above which the device will be destroyed.
Cut in voltage is the minimum voltage required to overcome the barrier potential. In other words it is like trying to push a large boulder....it may not be possible to push a large boulder by one person but it may be done if 2 or more people try to push it together depending on the size of the boulder.....similarly....the charge carriers in the barrier region have a potential energy of about 0.6V for Silicon and about 0.2V for Germanium. so in order for the diode to conduct, it is required to overcome the potential of the charge carriers in the junction barrier region and hence only if a potential more than that of the barrier potential (cut off voltage) is applied, then electrons flow past the junction barrier and the diode conducts.