###### Asked in Math and ArithmeticAlgebraCalculus

Math and Arithmetic

Algebra

Calculus

# What is the derivative function for square root 1-2x?

## Answer

###### Wiki User

###### March 28, 2008 5:16PM

derivative: -1(dx)/sqrt(1-2x)

## Related Questions

###### Asked in Math and Arithmetic, Algebra, Calculus

### What is the maximum value of the function y equals -6x2-12x-1?

y = -6x2 - 12x - 1
We recognize this as the equation of a parabola opening
downward, but we don't need to know that in order to answer the
question.
At the extremes of a function (local max or min), the first
derivative of the function = zero.
The first derivative of the given function with respect to 'x'
is dy/dx = -12x -12
Set -12x - 12 = 0.
-x - 1 = 0
x = -1
y = -6x2 - 12x - 1 = -6(1) - 12(-1) - 1 = -6 + 12
- 1 = 5

###### Asked in Math and Arithmetic, Calculus

### What is the anti-derivitive?

The inverse operation to the derivative. Also called the
integral. If you're given the derivative of a function, you can
find the function again by performing the antiderivative. Many
answers will be possible, all differing by a single number, so you
normally add a general constant to the end. Example : The
derivative of 6x^2 is 12x. The antiderivative of 12x is 6x^2 + any
number.

###### Asked in Algebra

### Determine the maximum or minimum value of y-3x2 12x-7 by completing the square?

Every polynomial defines a function, often called P. Linear and
and quadratic function belong to a family of functions known as
polynomial functions, which often are called P(x). When P(x) = 0,
we call it an equation. Any value of x for which P(x) = 0 is a
root of the equation and a zero of the function.
Polynomials of the first few degrees have a special names such
as:
Degree 0: Constant function
Degree 1: Linear function
Degree 2: Quadratic function
Degree 3: Cubic function
Degree 4: Quartic function
Degree 5: Quintic function
So, if we work a little bit to the given expression, we can turn
it in a polynomial function of the second degree.
y - 3x^2 = 12x - 7
y - 3x^2 + 3x^2 = 12x - 7 + 3x^2
y = 3x^2 + 12x - 7
Let's write y = f(x) and f(x) = 3x^2 + 12x - 7, where a = 3, b =
12, and c = -7.
Since a > 0, the parabola opens upward, so we have a minimum
value of the function. The maximum or minimum value of the
quadratic function occurs at x = -(b/2a).
x = -12/6 = -2
To find the minimum value of the function, which is also the
y-value, we will find f(-2).
f(-2) = 3(-2)^2 + 12(-2) - 7
f(-2) = 12 - 24 - 7 = -19
Thus the minimum value of the function is -19, and
the vertex is (-2, -19)
To find zeros, we solve f(x) = 0. So,
f(x) = 3x^2 + 12x - 7
f(x) = 0
3x^2 + 12x - 7 = 0 In order to solve this equation by completing
the square, we need the constant term on the right hand side;
3x^2 + 12x = 7 Add the square of one half of the coefficient of
x to both sides, (6^2)
3x^2 +12x + 36 = 7 + 36 Use the formula (a + b)^2 = a^2 + 2ab +
b^2;
(3x + 6)^2 = 43 Take the square root of both sides, and solve
for x;
3x + 6 = (+ & -)square root of 43
3x + 6 = (+ & -)(square root of 43) Subtract 6 to both
sides;
3x = (+ & -)(square root of 43) - 6 Divide both sides by
3;
x = (square root of 43)/3 - 2 or x = -(square root of 43)/3 -
2
The solution are (square root of 43) - 2 and
-(square root of 43) - 2

###### Asked in Math and Arithmetic, Algebra, Calculus

### Identify the maximum value of the function y equals -6x2-12x-1?

y = - 6x2 - 12x - 1 A second degree equation graphs as a
parabola, and has only one max or min. At that point, the first
derivative y' = 0. dy/dx = - 12x - 12 = 0 - x - 1 = 0 ==> x = -
1 At that point, y = - 6( 1 ) - 12( - 1 ) - 1 = - 6 + 12 - 1 = 5.
The max value of the function is 5, and occurs when x
= -1.

###### Asked in Math and Arithmetic, Algebra, Calculus

### What is the square root of x squared plus 12x -2 equals x plus 4?

It's a second-degree equation in 'x' that screams "trouble". But
we laugh in the
face of adversity and, with no thought for our personal safety,
we plunge right in
and pursue solution[s].
sqrt( x2 + 12x - 2) = x + 4
Square each side . . . . . . . . . . x2 + 12x - 2 = x2 + 8x +
16
Subtract x2 from each side . . . 12x - 2 = 8x + 16
Add 2 to each side . . . . . . . . . 12x = 8x + 18
Subtract 8x from each side . . . 4x = 18
Divide each side by 4 . . . . . . . . x = 9/2