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What is the derivative of cot?

Updated: 12/24/2022
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d/dx (cot x) = -csc2x

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Q: What is the derivative of cot?
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What is the derivative of cot x?

The derivative of cot(x) is -csc2(x).(Which is the same as -1/sin2(x).)


What is the derivative of cotx?

The derivative of cot(x) is -csc2(x).


What is the derivative of csc x?

The derivative of csc(x) is -cot(x)csc(x).


What is derivative of cot t dt?

d/dt cot (t) dt = - cosec2(t)


Second derivative of cosecx?

d/dx cosec(x) = - cosec(x) * cot(x) so the second derivative or d(d/dx)/dx cosec(x) = [- cosec(x) * d/dx cot(x)] + [ - d/dx cosec(x) * cot(x)] = [- cosec(x) * -cosec^2(x)] + [ - (- cosec(x) * cot(x)) * cot(x)] = cosec(x) * cosec^2(x) + cosec(x)*cot^2(x) = cosec(x) * [cosec^2(x) + cot^2(x)].


What is the anti-derivative of co secant x?

According to Wolfram Alpha, input:integral csc x it is -log[cot(x) + csc(x)] + constant You can verify this by taking the derivative of the purported integral.


What is the derivative of x equals cot2 divided by t?

Assuming you want dx/dt and that the equation is x = cot(2) / t (i.e. cot(2) is a constant) we can use the power rule. First, we rewrite it: cot(2)/t = cot(2) * t-1 thus, by the power rule: dx/dt = (-1) cot(2) * t-1 -1 = - cot(2) * t-2= = -cot(2)/t2


What is the derivative of 3tanx-4cscx?

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What is the second derivative of ln(tan(x))?

f'(x) = 1/tan(x) * sec^2(x) where * means multiply and ^ means to the power of. = cot(x) * sec^2(x) f''(x) = f'(cot(x)*sec^2(x) + cot(x)*f'[sec^2(x)] = -csc^2(x)*sec^2(x) + cot(x)*2tan(x)sec^2(x) = sec^2(x) [cot(x)-csc^2(x)] +2tan(x)cot(x) = sec^2(x) [cot(x)-csc^2(x)] +2


What is a cot-code?

what the definition of COT code and should I pay the bank for it?


What actors and actresses appeared in Cot Cot - 2007?

The cast of Cot Cot - 2007 includes: Emmanuel Bilodeau Rick Jones


What is the anti derivative of cscxcotx?

∫cscxcotx*dx∫csc(u)cot(u)*du= -csc(u)+C, where C is the constant of integrationbecause d/dx(csc(u))=-[csc(u)cot(u)],so d/dx(-csc(u))=csc(u)cot(u).∫cscxcotx*dxLet:u=xdu/dx=1du=dx∫cscucotu*du= -csc(u)+CPlug in x for u.∫cscxcotx*dx= -csc(x)+C