Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
Use Pythagoras' theorem: 33.9411255 or about 34 feet
46.648 ft
The diagonal of a 12' x 24' rectangle is approx 26.8'.
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
You use the Pythagorean Theorem, which says that the square of the hypotenuse of a right triangle is the sum of the squares of the other two sides. Two adjacent sides of a square (or any rectangle) together with a diagonal form a right triangle. In the case of a square, the triangle is isosceles. Calling the length of a side of the square (17 inches) one unit, the theorem tells us that the hypotenuse is the square root of 2 units. Therefore the diagonal of the square is 17 times the square root of 2 inches, which is about 24 inches.
Use Pythagoras' theorem: 33.9411255 or about 34 feet
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
Diagonal = 36.9 feet
36.8782 ft
46.648 ft
Using Pythagoras' theorem it is 8 times square root of 58 which is about 61 feet
The diagonal of a 12' x 24' rectangle is approx 26.8'.
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
2400 * 24 square units. However, since the measurement units are not specified, it is not possible to convert this to square feet.
The diagonal is approximately 38.42 feet.
The diagonal is 33.941 units.
diagonal^2 = 16^2 + 24^2 = 256 + 576 = 832 Therefore diagonal is square root of 832 = 28.8444 feet