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What is the dipole moment of CBr4?

Updated: 8/11/2023
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13y ago

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In the Periodic Table, oxygen is in Group VIA and fluorine is a halogen (Group VIIA)

Oxygen has 6 valence electrons and normally can form 2 single or 1 double bond (excluding the cases of its coordinate covalent bonds).

Fluorine has 7 valence and it can form only one single bond.

Therefore, for each O atom, 2 F atoms are needed to complete their octets to form a stable compound.

Fluorine is the most electronegative element, and attracts the bonding electrons to itself more than O. Therefore, the fluorine sides of the molecules become partially negative and oxygen become partially positive. (This is the single compound in which O has positive oxidation number).

If the molecule were linear, the centers of the positive and negative charges would coincide with each other, and the molecule would be nonpolar. But, because of the two nonbonding electron-pairs in the valence shell of O atom,

these pairs and bonding electron-pairs repel each other and the shape of the molecule becomes angular (bent) like water.

This causes an uneven charge distribution (separete centers of - and + charges) and the molecule becomes polar.

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15y ago
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12y ago

Oxygen difluoride is F2O, and is very similar to H2O. There's a great Wikipedia article that has a lot of information on it, if you want to know more.
OF2

Di means that there is two fluorine atoms and since oxygen is by itself, it means there is only 1 oxygen atom. Thus OF2

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14y ago

No, the electronegativity difference is zero and the molecule is symmetrical.

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14y ago

It is a symmetric tetrahedral molecule so has zero dipole moment.

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13y ago

Yes, it has a dipole moment because fluorine is more electronegative than oxygen

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6y ago

The dipole moment of oxygen difluoride is 0,3 D.

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13y ago

CBr4 does not have a dipole moment.

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12y ago

104 degrees.

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15y ago

OF2

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Q: What is the dipole moment of CBr4?
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