ELECTROMOTIVE MAGNETIC FORCE emf measured as volts . It does not guarantees a current or power but just the force is present. With a load it may disappear
The difference in reactivity of the electrodes.
Electro Motive Force, or amp/hours.
It depends on what cell is involved.
volts
Because emf is the very source of voltage, either chemical or inductive, an can be meassured at open circuit only so, internal resistance of the supplier is not affecting it.
to find the relation between emf generated and Field current .....
A voltmeter is used to measure voltage. A potentiometer is used to vary the amount of resistance in a circuit - it has nothing to do with measuring.
A magnetic field will not generate an EMF if there is no motion, so the primary factor causing a permanent magnet generator to not generate EMF is if it is not turning.
Well, you should really measure the open-circuit voltage and the short circuit current both under dark and light conditions and then compare them to fully characterize a solar cell. Measuring the open-circuit voltage means measuring the voltage across the cell when no current is flowing (i.e., with a LARGE resistance as a load on the cell). Measuring the short-circuit current means measuring the current when the voltage across the circuit is essentially zero (i.e., with a VERY SMALL resistance as a load on the cell--thus, "short-circuit" current).
in an open circuit, i.e. no current drawn from the cell, producing no drop across its internal impedance
The potentiometer is designed in such a way that no current is taken from the circuit you are measuring.
With cells connected in series, the total emf of the 'stack' is simply the sum of the individual emf's of the individual cells. -- Even if one cell is connected backwards in the string. Then its emf is considered negative when the sum is being performed. -- All of this is true only as long as there is no external connection between the ends of the stack, you're measuring the emf on an 'open-circuit' basis with a voltmeter, and the cells are not providing any current to an external circuit. Once the series combination of cells is connected to an external circuit and begins to produce current, the total emf at the terminals of the stack will decrease. It'll depend on the magnitude of the current, and on the 'internal impedance' of each cell. If the cells are not precisely identical and in identical states of charge, then a calculation of the total emf is virtually impossible.
Because emf is the very source of voltage, either chemical or inductive, an can be meassured at open circuit only so, internal resistance of the supplier is not affecting it.
Bcoz the emf which is to be measured is less than emf of driving cell....
to find the relation between emf generated and Field current .....
No. But if you increased the EMF across the circuit, then more electrons would flow through it each second.
You can measure the emf of a cell by using a voltmeter, as this draws current from a cell. You can use the voltage, the emf, and the load resistance to determine the internal resistance of the cell.
No. But the current through it does.
it is called a circuit and when it is closed is called a closed circuit and when open circuit it is called an open circuit
It suggests that :- An EMF is set Up in circuit when the magnetic flux linking the circuit is changed in any manner.The magnitude of this EMF is proportional to the time rate of flux linkage with circuit.
12v