In beta decay, we see one of two things happening. In one case, a proton in an atomic nucleus is converted into a neutron (beta minus decay) and a new element is formed with the ejection of an electron and an antineutrino. In the second case, a neutron in an atomic nucleus is converted into a proton (beta plus decay) and a new element is formed with the ejection of a positron and a nuetrino. If we were to write the formulae for these reactions we'd have to "generalize" them since we won't specify an element. But we can just pick two examples and post them. We see that carbon-14 undergoes beta minus decay to become nitrogen-14 in this equation: 614C => 714N + e- + ve The carbon-14 nucleus has a neutron within it change into a proton Then we see both a beta minus particle, an electron with high kinetic energy, and an antineutrino ejected from the nucleus. When sodium-22 undergoes beta plus decay to become neon-22, it looks like this equation: 1122Na => 1022Ne + e+ + ve The sodium-22 nucleus has a proton within it change into a neutron. We'll then see a beta plus particle, a positron (an antielectron) with high kinetic energy, and a neutrino ejected from the nucleus. That's the long and short of it. Use the link below to learn more about beta decay. It will lead you to, "What is beta decay?" here on WikiAnswers, and it has been answered.
Zinc-64 is stable; there is no decay equation.
The equation for the beta decay of 72Zn:
3072Zn --> 3172Ga + -10e
where the e is an electron.
3H --> 3He + 0e- + 18 KeV
Source: The Radiochemical Manual, Part 1: Physical Data (1962)
uranium 235 decays by gamma not beta uranium-235 + neutron = uranium-236 = Neptunium-236 + beta-
Cu-64 (copper)
0
e
-1
The only hydrogen isotope that undergoes any type of radioactive decay is tritium (hydrogen-3), it undergoes beta decay to become helium-3. If that's not what you were asking about, I'm confused by your question.
The equation for the positive beta decay of 188Hg is: 80188Hg --> 79188Au + 10e where e indicates a positron or positive beta particle.
229Th-------alpha particle-----------225Ra
Nope, Neodymium-144 undergoes Alpha decay to Cerium-140.
uranium 238 is a fast neutron absorber the answer is correct but for more explanation:- when uranium 238 is bombard by neutron >>> uranium 238 , undergoes B decay>>>Np 239 ,undergoes B decay >>> Pu 239 finally undergoes alpha decay >>> fissile U
The equation for the beta decay of 137Cs:55137Cs --> 56137Ba + -10e where the e is a negative beta particle or electron.
Po-216- -----------------> Pb-212
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
92Au 282Xe +13S
224
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
For nuclear decay, you must also specify what isotope you are talking about. Just saying "Sulfur" simply isn't enough information.
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
The only hydrogen isotope that undergoes any type of radioactive decay is tritium (hydrogen-3), it undergoes beta decay to become helium-3. If that's not what you were asking about, I'm confused by your question.
lithium
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
Americium-244 undergoes beta decay: 95244Am --> 96244Cm + -10e where -10e is a negative beta particle or electron.