Points: (4, 8) and (2, -2)
Slope: (8--2)/(4-2) = 5
Equation: y-8 = 5(x-4) => y = 5x-12
Equation: y--2 = 5(x-2) => y = 5x-12
So straight line equation is: y = 5x-12
If the points are (1,5) and (0,0) y = 5x
Slope=8 point=(-7,3)
Points: (4, 5) and (-3, -1) Slope: 6/7 Equation: 7y = 6x+11
Points: (-1, 7) and (-2, 3) Slope: 4 Equation: y = 4x+11
Points: (9, 1) and (4, 16) Slope: -3 Equation: y = -3x+28
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Points: (4, 8) and (2, -2)Slope: 5Equation: y = 5x-12
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Assuming the point is (9, -4), the equation is y = -4.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is: y = 4x-22
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).