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The exact value of 60 degrees would be 1/2. This is a math problem.
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What is the exact value of tan -60?
tan(-60 degrees) = - sqrt(3)
What is the exact value answers in degrees of two cos x minus radical three equals zero?
30 degrees explanation 2Cosx-radical 3=0 Then 2cosx=radical 3 and cos x=(radical 3)/2 Now remember that cos 300 is (radical 3)/2 from the 30/60/90 triangle. So the answer is 30 degrees.
What is the tangent of 60 degrees?
the tangent of 60 degrees is 1.7321
What is sin cos tan csc sec cot of 30 45 60 degrees?
Sin(30) = 1/2 Sin(45) = root(2)/2 Sin(60) = root(3)/2 Cos(30) = root(3)/2 Cos(45) = root(2)/2 Cos(60) = 1/2 Tan(30) = root(3)/3 Tan(45) = 1 Tan(60) = root(3) Csc(30) = 2 Csc(45) = root(2) Csc(60) = 2root(3)/3 Sec(30) = 2root(3)/3 Sec(45) = root(2) Sec(60) = 2 Cot(30) = root(3) Cot(45) = 1 Cot(60) = root(3)/3
Is the cosine function an odd function?
No. Cosine, along with sec, is an even function. The odd functions are sin, tan, csc, and cot. The reason for this is because is you take the opposite of the y-value for the cosine function, the overall value of the function is not affected.Take, for example, cos(60 degrees), which equals POSITIVE 1/2.If you flip it over the x-axis, making the y's negative, it becomes cos(-60 degrees), or cos(300 degrees). This equals POSITIVE 1/2.Now let's look at an odd function. For example, sin(30 degrees) equals POSITIVE 1/2. Now take the opposite of this.sin(-30 degrees), or sin(330 degrees), equals NEGATIVE 1/2. This is because it is found in the fourth quadrant, where the y's are negative. Sine of theta, by definition, is y divided by r. If y is negative, sine is negative.
What is the exact value of tan -60?
tan(-60 degrees) = - sqrt(3)
What is the value of sin60?
sin(60 degrees) = 0.8660 approx. The exact value is sqrt(3)/2.
What is tan 60 degrees?
1.732
The function cot 115 degrees is equivalent to A -tan 60 degrees B -tan 25 degrees C tan 25 degrees D tan 65 degrees?
cot 115 deg = - tan25 deg
How do you get angle size of a 60 feet multiply 90 feet?
5400
What is the exact measure of acute angle?
60 degrees
What is tangent of pie divided by 3 equal to?
tan(pi/3) = tan (60 degrees) = 1.732 which is square root of 3
What is the exact temperature in numbers before a hurricane?
IT could anywhere from 60-80 degrees. There's no exact temp.
What is A boat moves at an angle of 60 in a horizontal line The x component of the boats velocity is 5 m s What is its y component of velocity?
You have a right triangle and can use trig. Degree mode. tan(theta) = adjacent/opposite( y component ) tan( 60 degrees) = (5 m/s)/(y comp.) y component = 5 m/s)/(tan 60 degrees) = 2.887 m/s ( you can call it 3 m/s ) -----------------------------------------------
Convert gps reading n27 degrees 18.773 minutes to degrees only?
There are 60 minutes in a degree, so 18.773'/60 = .3129 degrees, and your final value is north 27.3129o.
What are all the exact values for which tan t equals sqrt3?
sin(60) or sin(PI/3) = sqrt(3)/2 cos(60) or cos(PI/3)=1/2 tan(60) or tan(PI/3) = sin(60)/cos(60)=sqrt(3) But we want tan for -sqrt(3). Tangent is negative in quadrant II and IV. In Quadrant IV, we compute 360-60=300 or 2PI-PI/3 =5PI/3 tan(5PI/3) = -sqrt(3) Tangent is also negative in the second quadrant, so we compute PI-PI/3=2PI/3 or 120 degrees. tan(t)=-sqrt(3) t=5PI/3 or 2PI/3 The period of tan is PI The general solution is t = 5PI/3+ n PI, where n is any integer t = 2PI/3+ n PI, where n is any integer
Why Ten90' is infinity?
First, I assume the question refers to tan(90 degrees) not Ten90' because (apart from the incorrect spelling of tan) 90' represents 90 minutes or 90/60 degrees = 1.5 degrees. The tangent of an angle is defined as the ratio of sine to cosine of the angle. When that angle is 90 degrees, the cosine is zero and so calculation of tan involves division by 0. And, in mathematics division by 0 is not infinity - it is not defined. So, tan(90) is NOT infinity. It is not defined. tan90 has a positive asymptote when you approach 90 degrees from below but has a negative asymptote when you approach from above.
