3x2 - 3x - 60
= 3(x2 - x - 20)
= 3(x2 - 5x + 4x - 20)
= 3(x[x - 5] + 4[x - 5])
= 3(x + 4)(x - 5)
Assuming the missing signs are pluses, that factors to 3(x + 1)2
3(x + 4)(x + 5)
(2x + 7)(5x - 4)
(3x - 2)(x + 4)
3x(x + 4)(x - 2)
x(x + 5)(x + 8)
It is: (3x+27)(x+3)
3x^3 + 6x^2 - 24x = 3x*(x-2)*(x+4)
(3x - 4)(x - 1)
54 6 x 9 3x2 3x3 Answer: 3to the 3rd power times 2 3^3x2
If that's 3x2 - 7x + 4, the answer is (3x - 4)(x - 1)
two factors is a binomial three factors is a trinomial four of more is a polynomial the product of any of these is just a polynomial
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-3 plus or minus 2i times the square root of 3) divided by 3.x = -1 + 1.1547005383792515ix = -1 - 1.1547005383792515iwhere i is the square root of negative one.
3x2 + 27x +60
3x2 + 36x + 81 = 3(x2 + 13x + 27)
-(3x - 4)(x - 2)
-(3x+4)(x+2)
3x2 + 27x = 30 ∴ x2 + 9x - 10 = 0 ∴ (x + 10)(x - 1) = 0 ∴ x ∈ {-10, 1}
It is: (-3x-4)(x+2) when factored
Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored
(3x+1)(x+2)
3x2+7-6 = (3x-2)(x+3) when factored
3x2 + 36x + 81 = 3(x2 + 12x + 27) = 3(x + 3)(x + 9), which are its prime factors; or, if you prefer, 3x2 + 36x + 81 = (3x + 9)(x + 9), which is also accurate. You may easily verify these results by multiplying back.
3x2 + 10x + 3 = (x + 3)(3x + 1).
(3X + 9) (X + 9)