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What is the final concentration if 75.0 mL of a 3.50 M glucose solution is diluted to a volume of 400 mL?
Wiki User
∙ 9y ago
A 1 mole glucose solution means that there would be 1 mol/liter. There is only .075 liters, so there is only .075 moles present. .075 moles in 400 milliliters is a .075 to .4 ratio. By expanding the ratio, it is found that there are .1875 moles to 1 liter, making the final concentration 0.1875 M.
Wiki User
∙ 9y ago
Wiki User
∙ 9y agoM1*v1=m2*v2
m1=(75.0*3.50)/400
m1=0.65625
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