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The Jetta engine should fitAnswerAny four-cylinder watercooled VW engine will FIT in the car; every watercooled inline-4 Volkswagen engine has the same bellhousing pattern and mounting bolt hole locations. The question is, which engines will work? And really, because of all the electronics in your car I wouldn't guarantee anything but another 1.8 Turbo would work.

The width of the room is equal to twice the Length. Suppose Length = L, width = W, and A = areaW = 2L from the information in the questionNow we know area, A is equal to length times widthW*L=A, plug in 2L for W and we get 2L*L=A or 2L^2=ANext, we see that when 6 is subtracted from both length and width A becomes 108 less.So (2L-6)*(L-6)=A-108Multiply (2L-6)*(L-6) out and the result is (2L^2-18L+36) Set that equal to A-108(2L^2-18L+36)=A-108. We found out that A=2L^2 earlier so we can substitute the terms.(2L^2-18L+36)=2L^2-108. Now solve for LSubtract 2L^2 from both sides(-18L+36)=(-108)Subtract 36 from both sides(-18L)=(-144)Divide by (-18)L=8We know W=2L so W=16Now lets test our answer.16*8=128(16-6)*(8-6)=10*2=20128-20=108So the answer of L=8 and W=16 is correct.

The F-18 was based on the YF-17 (the aircraft that "lost" the USAF LWF [Lightweight Fighter Program] ). The YF-17 was a development of the P-530 Cobra (which, in turn, was a roundabout development of the F-5 Freedom Fighter). All of these aircraft were a product of Northrop, with McDonnell-Douglas providing much input at the stage between YF-17 and F-18 as completed. The agreement between the two firms was that MDD would produce the naval variants (F-18, which became the F/A-18) and Northrop would produce the land-based versions (F-18L). Unfortunately for Northrop there were no orders for the F-18L.

I have a 2001 1.8T Passat Station Wagon. My (non-dealer) repair shop suggests that premium gas is only required for city driving. When going on a long trip with mostly high speed interstate driving, mid-grade gas is okay according to them. I have been following their advice for the last year and have had no change in gas mileage or performance. As a once owner of a 2000 Passat wagon, a brother-in-law who has spent over the last 20 years as a VW dealer tech and he too still owns his 2000 Passat wagon 1.8T has never used anything but regular unleaded gas in his car. He says there is no reason that he has ever known or experienced in his many years as a tech and owner to use premium gas in this car. With the 1.8T you should only be using a full synthetic oil. there is no way around this. Using conventional motor oil WILL cause sludge in your engine, void the extended warranty on this engine and cost thousands to fix.

The figure could be a rectangle with length 6.79 and width 2.21(2dp). Area (A) of a rectangle = Length (L) x Width (W) = 15 : Then W = 15/L Perimeter = 2(L + W) = 18 : substituting for W then :- 2(L + 15/L) = 18 : 2L + 30/L = 18 : 2L2 - 18L + 30 = 0 Solving for a quadratic equation gives L = (18 ยฑ โ84) รท 4 = 4.5 ยฑ โ5.25 = 4.5 ยฑ 2.29(2dp)

Let L be the length of the rectangle. Since the length of the side of the square is the same as the width of the rectangle and the width of the rectangle is its length minus 6, the length of the side of the square is (L-6) and the area is (L-6)2. Since the width of the rectangle is its length minus 6, its area is L(L-6). Here is some of the work: 176 = (L-6)2 + L(L-6) 176 = (L-6)(L-6) + L(L-6) 176 = L2 - 6L - 6L + 36 + L2 - 6L 176 = 2L2 - 18L + 36 140 = 2L2 - 18L 70 = L2 - 9L 70/L = L - 9 (9L + 70)/L = L L = (9L+70)/L L2 = (9L+70) L = sqrt(9L+70) According to WolframAlpha (www.wolframalpha.com), L=14. (But don't say L; use x). The length of the side of the square is 8 m, which is also the width of the rectangle; the length of the rectangle is 14 m; the area of the square is 64 m2; and the area of the rectangle is 112 m2.

Let w equal the width and l equal the length of the rectangle. This means that 2w+2l=135 and since the rectangle has a scale factor of 8:1, that w/l=8. We now have a system of equations. Solve the second equation for w and find that w=8l. Substitute this into the first equation and find that 2(8l)+2l=135, which simplifies to 18l=135. Solve for l to get l=7.5 units. Plug this into either of the original equations to find that w=60 units. The dimensions of the rectangle are 60 by 7.5 units.

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