chromium (III) acetate
at least this is what masteing chemistry told me after I guessed wrong three times I however am not to sure because my chem. teacher "doctor" Ott did not bother teaching me how to figure this out before she assigned it for homewor
CrCO3 is the formula. The name of this compound is chromium II carbonate.
This formula is for chromium acetate.
The formal of this compound is Al2(CrO4)3. The name of it is aluminum chromate.
Chromium (VI) carbonate
The name CuCO3 is Copper (II) Carbonate.
CoO3 Cobalt Trioxide?
Chromium oxide: 2Cr3+ + 2O2- --> Cr2O3
Cr(C2H3O2)2 is chromium(II) acetate
Cr+3 C2H3O2-1 <----- these are the ions and their charges Cr+3 C2H3O2-1 C2H3O2-1 C2H3O2-1 <---- the charges have to add up to zero, so three -1 acetate ions cancel out one +3 chromium ion Cr(C2H3O2)3 <----- simplify
Er(C2H3O2)3
B(c2h3o2)3
CrNO3 ************2nd Opinion*********** To get the correct formula, you need to state the oxidation number of chromium in the compound, using a Roman numeral. It's likely to be chromium(III) nitrate, which is Cr(NO3)3
chromium(III) oxalate [Cr(ox)3]3- this is the actual formula. Chromuim (III) oxalate is the name of the complex. The (ox) being the ligands attached to the metal centre.
Cr+3 C2H3O2-1 <----- these are the ions and their charges Cr+3 C2H3O2-1 C2H3O2-1 C2H3O2-1 <---- the charges have to add up to zero, so three -1 acetate ions cancel out one +3 chromium ion Cr(C2H3O2)3 <----- simplify
3 +
Er(C2H3O2)3
B(c2h3o2)3
Assuming that the questioner meant the formula to be Al(C2H3O2)3, which the questioner probably was unable to write on a normal keyboard, the answer is aluminum acetate.
Fe(C2H3O2)3.
The formula is Ga(CH3COO)3
The formula for iron(II) acetate is to my knowledge Fe(C2H3O2)2. And iron(III) acetate is to my knowledge Fe(C2H3O2)3.
Al(C2H3O2)3 - first, aluminium is in the beginning of the equation and acetate needs to be after. Aluminium has a charge of +3 making it Al+3 -acetate has a charge of -1 and its formula is C2H3O2- Using the crossover method, we see that it would take three acetate ions (-1 charge) to balance out the 1 Aluminium Ion (+3 charge). So the final equation should be Al(C2H3O2)3
CrNO3 ************2nd Opinion*********** To get the correct formula, you need to state the oxidation number of chromium in the compound, using a Roman numeral. It's likely to be chromium(III) nitrate, which is Cr(NO3)3
chromium(III) oxalate [Cr(ox)3]3- this is the actual formula. Chromuim (III) oxalate is the name of the complex. The (ox) being the ligands attached to the metal centre.
The answer from my chem class states its Cr(NO3)2