The formula, which is simpler to apply than to write out(!) is
If
X1 = pa1qb1rc1 ...
and
X2 = pa2qb2rc2 ...
where p, q, r etc are prime numbers and a, b, c etc are integers.
Then
LCM(X1, X2) = pmax(a1,a2)*qmax(b1,b2)*rmax(c1,c2) ...
Yes. For two prime numbers, the LCM is their product: one times the other. Multiply the two. (e.g. LCM of 5 and 7 is 35) By formula, the LCM for x and y is LCM = x * y / GCF and for primes, the GCF (greatest common factor) is 1.
The LCM is: 52
The LCM is: 270
The LCM is 392.
LCM of 15 and 2 is 30.
84
Least Common Multiple of 454 and 463 with GCF Formula The formula of LCM is LCM (a,b) = (a × b) / GCF (a,b). We need to calculate greatest common factor 454 and 463, than apply into the LCM equation. GCF (454,463) = 1
It is: 630 by finding the prime factors of the given numbers
2 * 3 = 6 3 * 3 = 9 LCM = 2 * 3 * 3 = 18 You can verify this by checking the formula: gcd(a,b) * LCM(a,b) = a * b 3 * LCM(6,9) = 54 LCM(6,9) = 18
Yes. For two prime numbers, the LCM is their product: one times the other. Multiply the two. (e.g. LCM of 5 and 7 is 35) By formula, the LCM for x and y is LCM = x * y / GCF and for primes, the GCF (greatest common factor) is 1.
There is no exact formula. To find the sequence of LCMs see http://oeis.org/A003418/list. LCM(1, 2, 3, ..., n) tends to en as n tends to infinity. Equivalently, ln[LCM(1, 2, 3, ..., n)] tends to n or ln[LCM(1, 2, 3, ..., n)] / n tends to 1 as n tends to infinity.
The LCM is: 210
The LCM of these numbers is 50. LCM is Least Common Multiple.
The LCM for 52, 14, 65 and 91 is 1,820
The LCM is: 10The LCM is 10.
You can't find the LCM of a single number. The LCM of 1, 2, 3 and 14 is 42.
The LCM of these numbers is 340. LCM is Least Common Multiple.