What is the complete ionic equation for lead nitrate and potassium sulfate?

Answer 1

AnswerThese substances react by double displacement.

Pb(NO3)2(aq) + K2SO4(aq) = PbSO4(s) + 2KNO3(aq)

The Lead(II) Sulphate formed (i.e. PbSO4(s)) is obtained as a white precipitat. Potassium Nitrate solution (KNO3(aq)) is colourless.

Answer 2

Balanced Chemical Equation

Pb(NO3)2(aq) + K2SO4(aq) ---> PbSO4(s) + 2KNO3(aq)

Complete Ionic Equation

Pb2+(aq) + 2NO3-(aq) + 2K+(aq) + SO42-(aq) ---> PbSO4(s) + 2K+(aq) + 2NO3-(aq)

Answer 3

Pb^(2+)(aq)+2NO3^(-)(aq)+2K^(+)(aq)+SO4^(2-)(aq)====>Pb(SO4)(s)+2K^(+)(aq)+2NO3^(-)(aq)

Answer 4

Pb(NO3)2(aq) + K2CO3(aq) → 2KNO3(aq) + PbCO3(↓)

Answer 5

lead II nitrate with potassium bromide is Pb(NO3)2+2KBr --> PbBr2+2KNO3 Balanced

Answer 6

The chemical formula of lead(II) nitrate is Pb(NO3)2.

The chemical formula of potassium sulfate is K2SO4.

Answer 7

Lead (II) Nitrate is Pb(NO3)2

Potassium Hydroxide is POH

Answer 8

Pb(NO3)2 + 2KOH --> Pb(OH)2 + 2KNO3

Answer 9

Pb(NO3)2 + 2KI --> PbI2 + 2KNO3