The formuls of the compound barium nitrate is Ba(NO3)2. The question as stated has no unique answer, because many other compounds can be formed from barium nitrate, depending on what else is available to react with the barium nitrate.
2Ba(NO3)2(s) -----> 2BaO(s) + 4NO2(g) + O2(g)
On heating: 2NaNO3 → 2NaNO2 + O2
The products are sodium nitrite and oxygen gas.
2Ca(NO3)2 » 2CaO + 4NO2 + O2
no
barium nitrate + sulphuric acid gives barium sulphate equation is BaNo3 + SO4 - BaSO4
Copper nitrate and barium chloride do not react. Barium chloride solution produces a white precipitate with solutions containing sulfate ions.
There shall be none as both compounds have same anions (Nitrates)
Nh3+4hj
SO42- + Ba2+ --> BaSO4
barium nitrate + sulphuric acid gives barium sulphate equation is BaNo3 + SO4 - BaSO4
Ba(NO3)2
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
Copper nitrate and barium chloride do not react. Barium chloride solution produces a white precipitate with solutions containing sulfate ions.
lead II acetate and barium chloride equation
There shall be none as both compounds have same anions (Nitrates)
Nh3+4hj
SO42- + Ba2+ --> BaSO4
Barium nitrate is dissociated in water.
Barium Nitrate is Ba(NO3)2.
The barium nitrate phrase is R20/22.
Ba(NO3)2 + 2NaOH → Ba(OH)2 + 2NaNO3Barium nitrate + sodium hydroxide → barium hydroxide + sodium nitrate