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Answered 2008-06-12 17:21:25

== Molality== (1000xMolarity)/((1000xdensity of solution)- (MolarityxMolecular weight of Solute)) ==

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Molarity is defined as grams of solute dissolved in 1 liter of solution and molality is defined as grams of solute dissolvd in 1Kg of solvent


Looks like someone is a bit lazy doing his/her homework... anyway: Molarity is the number of moles present in a volume of 1 litre. (Moles/L) Molality is the number of moles present in 1 kg of solution. (Moles/Kg) Density, is mass per volume. (should be in Kg/L) First think intuitively. MolaRity = molaLity when 1 L is the same amount of matter than 1 Kg. That's when the density of the solution is 1 Kg/L. If the solution is more dense, then the same volume holds more mass, so MolaRity > molaLity. This relation is proportional to the density, so... you can work out the formula. Another way of looking at the problem is doing dimensional analysis (some call it cheating... it's that great!): You need Moles/L and you have two magnitudes expressed in Moles/Kg and Kg/L. The only way you can cancel out those Kg is by simply multiplying them: Moles/Kg x Kg/L = Moles/L Molality x density = Molarity Voila! problem solved


The molality is the ratio between the mass of a solute (expressed in moles0 and the mass of the solvent (expressed in kilograms). The term is now anachronic.


molality (m) = (No. of moles of solute) / (weight of solvent in kilograms)



MOLARITY = mole of solute / L solution


you use the formula.... molality(m)=moles of solute divided by kilograms(kg) of solvent


# of moles of solute Molarity = -------------------------- 1 Liter of solution


Molarity = Grams/(Molecular Weight X Volume)


Calculating the freezing point depression of a solvent requires three pieces of information: 1) the molal freezing point depression of that solvent; 2) the molality of the solution; 3) the number of distinct entities produced in solution per molecular formula unit of solute. Hopefully you meant molality instead of molarity (if the solvent is water and it's a dilute solution, assuming that molality = molarity isn't a bad approximation). I suspect you've been told what 1 and 3 are (or been given enough information to figure them out) but simply didn't mention it; otherwise you're pretty much boned.


Molarity = moles of solute/Liters of solution


molality= moles solute/kg solvent b= n / m b - molality n - moles solute m - kg solvent, not: kg solution!


(moles of solute) / (kg of solvent) different from Molarity with a capital 'M'.


it is M=g/L where m=molarity, g= grams, and l= liters.


nomality =molarity*valancy factor


The addition of a non-volatile solute elevates the boiling point of a solution (in addition to the depression of freezing point). The formula is ΔT = Kbm where ΔT is the change in temperature, Kb is the ebullioscopic constant, and m is the molality (not molarity) of the solution.


Molality is the number of moles of solute dissolved in one kilogram of a solvent. It is found by dividing the number of moles of solute by the weight of solvent measured in kilograms.


There are several formulae involving molarity, depending on what you are measuring. However the simplest is; If you have x moles of solute in y ml of solution, Molarity = 1000 x/y


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This is the ratio concentration of a solute/molar mass of the solute.


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the formula showing the relation between the unit of any physical quantity n the unit of fundamental physical quantity is called dimensional formula.........of dat quantity


molarity (M) is the concentration of moles (n) of a solute per liters (v) of solution M=n/v


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