Let y=sin i, x=sin r then y=nx where n is refractive index. A straight line with slope n.
The graph of the function y = (sin x)^2 has the same amplitude 1, and the same period 2pi, as the graph of the function y = sin x. The only difference between them is that the part of the graph of y = sin x which is below the x-axis is reflected above x axis. In order to graph the function y = (sin x)^2, we need to find the values of (x, y) for the five key points, where 0 ≤ x ≤ 2pi. Values of (x, y) on y = (sin x)^2: x = 0, y = 0 x = pi/2, y = 1 x = pi, y = 0 x = 3pi/2, y = 1 x = 2pi, y = 0 Plot these five key points and connect them with a smooth curve and graph one complete cycle of the given function.
The simplest way is to use a graphing calculator such as a TI-83. To enter in the graph do the following... 1) Hit "Y=" (It should be located in the upper left hand corner) 2) Enter the function = 4 sin (3x) Use the X,T,Theta,N button for "x" 3) Hit "Graph" Please note, make sure your calculator is in Degree Mode, and the graph is set to a "Functional" graph. To check this hit the mode button. Degree and Func should be highlighted. -------------------------------------------------------------------------- You can also draw this by hand here's how... First you need to understand the important values of sin x sin(0) = 0 sin(30) = ½ sin(60) = √3 / 2 sin(90) = 1 sin(120) = √3 / 2 sin(150) = ½ sin(180) = 0 These are important because they are part of the unit circle. Notice the repeating pattern. The important points are 0, 30, 90, 150, 180 We can plot those on a graph then we see an oscillating wave that repeats. But this would be for ƒ(x) = sin (x) Instead the 3x on the inside means we are looking for values which make our sin the same We find these by dividing the special points by 3. 0,10,30,50,60 So on those x values we will put a coordinates. Now we have to determine the y values of the coordinates. To find these we just multiply by the coefficient 4. 4 sin (3*00) = 0 4 sin (3*10) = 4/2 = 2 4 sin (3*30) = 4 4 sin (3*50) = 4/2 = 2 4 sin (3*60) = 0 Now we have our points (00,00) (10,02) (30,04) (50,02) (60,00) We plot these and then connect them on a graph to create an oscillating wave...
it is the same as a sin function only shifted to the left pi/2 units
y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.
No.-1
no
the range is greater then -1 but less than 1 -1<r<1
sin(0) = 0 but, in general, the sine graph need not start at 0. For example, sin(x + 2) does not start at 0.
It depends on the medium the light is passing through n sin I=n sin R
All prophets warned man against sin.
He will not hold the sin against you.
ecological sin is a sin of every individual against the environment....
A graph of distance against time.
It is zero.
If you want the graph to show the acceleration of the ball against time, then the graph is a horizontal line. If you want the graph to show the velocity of the ball against time, then the graph is a straight line sloping downward. If you want the graph to show the height of the ball against time, then the graph is a parabola that opens downward.
The answer depends on the variables in the graph! In a graph of age against mass there is nothing that represents acceleration.
You put the acceleration on the x-axis, and sin theta on the y-axis