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If we assume the "planet" is Earth, we can calculate the gravitational force at roughly 196 N (20x9.8 = 196). This assumes that the object is close enough to the surface that the change in distance between now and when it impacts the planet surface is negligible (which, if it is already falling at 10 m/sec it probably would be) so that we can use standard gravitational acceleration as a reasonable estimate in calculating the force. Note that the velocity at which it is falling is irrelevant in calculating the gravitational attraction.

As noted in the expert answer though, the question is posed with too many undefined important variables to give a definitive answer without making a lot of assumptions.

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7y ago
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11y ago

F = G M1M2/R2

G = 6.67384 x 10-11 newton-meter2 / kilogram2

Force = (6.67384 x 10-11) (20)(20)/25 = 1.0678 x 10-9 newton = 0.000 000 003 84 ounce

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9y ago

Gravitational force =

(G) (mass-1) (mass-2) / (distance squared)

G = 6.67 x 10^-11 newton meter-squared/kg-squared

Force = (6.67 x 10^-11) (1) (1) / 1

Force = 6.67 x 10^-11 newton

That's about 0.000 000 000 24 ounce, which is why

we're never aware of it..

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12y ago

There's not enough information here to derive an answer to the question ...

at least not a meaningful answer.

-- The force between the planet and the mass depends fundamentally on both

of their masses and on the distance between their centers. We only know one

of these three numbers, so we need another way to find the force.

-- The force on any object is (its mass) x (its acceleration). We know the mass

of the mass . . . it's 20 kilograms. If we can find its acceleration, we can calculate

the force on it.

-- A "freely falling" body is accelerating downward. The mass in this question is

falling at [constant] 10 meters per second. It's not freely falling, and its acceleration

is zero.

-- Since its acceleration is zero, the sum of all the forces on it is zero. There are

two ways this could happen, and we don't have enough information to figure

out which it is (except that one of them is ridiculous):

. . . The planet could have an atmosphere, and 10 meters per second might be

the object's terminal velocity, at which the force of air resistance is equal to the

force of gravity, and acceleration stops.

. . . The planet might have no atmosphere and zero mass. That would explain why

a freely falling object is not accelerating ... the gravitational force on it is zero.

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11y ago

F = G M1M2/R2 = (6.67 x 10-11) (1)(1)/(1)2

= 6.67 x 10-11 newton

= 0.00000000024 ounce (rounded)

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11y ago

Just plug the numbers into the formula for gravitational attraction. The answer should be in newton, by the way.

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13y ago

5.9 x 10^-10 N

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9y ago

F = 59.31 newtons.

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11y ago

40.9876x200

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Q: What is the gravitational force between a mass of 20kg and a mass of 100kg that are 15meters apart?
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