It's a sp2 hybridisation.
This is an odd question. Hybridisation is a "trick" used in valence bond theory to form orbitals that have the correct geometry and optimise orbital overlap. In principle you can mathematically hybridise orbitals of suitable symmetry. Typically in valence bond theory you see s and p orbitals hybridised to sp, sp2 and sp3 hybrids and , s, p and d orbitals forming sp3d and sp3d2
In chemical bonding hybridisation is a mathematial device used in valence bond theory to devise new orbitals from the base atomic orbitals - the aim being to achieve new obitals that "point" in the right direction- so tetrahedral methane - use sp3 hybrid orbitals as these hybrid orbitals point tetrahedrally.
Krypton is a noble gas and hence has stable electronic configuration. Its valence shell configuration is 4s2 4p6 . Therefore, it has 1-s and 3-p full orbitals in its valence shell.
I suspect the word you're looking for is "degenerate."
26 sigma 7 pi
In valence bond theory it is assumed the four electron pair bonds reside tetrahedrally about the carbon giving rise to the terahedral shape of the molecule. sp3 hybridisation is "necessary", it replaces the s , px, py and pz orbitals with four orbitals of identical energy (degenerate) with lobes pointing to corners of a tetrahedron- the 4 electrons are then promoted to these orbitals - the hybridisation energy.
Hybridisation is a mathematical technique in valence bond theory used "create" new (higher energy) orbitals from base atomic orbitals so that the new orbitals point along bond axes. Valence bond theory as its name suggests focuses on the localised electron pair. Other bonding theories such as molecular orbital theory do not hybridise the base atomic orbitals. Both theories have their merits.
This is an odd question. Hybridisation is a "trick" used in valence bond theory to form orbitals that have the correct geometry and optimise orbital overlap. In principle you can mathematically hybridise orbitals of suitable symmetry. Typically in valence bond theory you see s and p orbitals hybridised to sp, sp2 and sp3 hybrids and , s, p and d orbitals forming sp3d and sp3d2
In chemical bonding hybridisation is a mathematial device used in valence bond theory to devise new orbitals from the base atomic orbitals - the aim being to achieve new obitals that "point" in the right direction- so tetrahedral methane - use sp3 hybrid orbitals as these hybrid orbitals point tetrahedrally.
Hybridisation is a mathematical technique in valence bond theory used "create" new (higher energy) orbitals from base atomic orbitals so that the new orbitals point along bond axes. Valence bond theory as its name suggests focuses on the localised electron pair. Other bonding theories such as molecular orbital theory do not hybridise the base atomic orbitals. Both theories have their merits.
The hybridisation of sulfur is sp3. The structure is often drawn with two double bonds, with double bond formed from d orbitals on sulfur and p orbitals on oxygen. This is the Pauling valence bond 1940's approach. More recent work suggests that the involvement of d orbitals is minimal.
The hybridisation of sulfur is sp3. The structure is often drawn with two double bonds, with double bond formed from d orbitals on sulfur and p orbitals on oxygen. This is the Pauling valence bond 1940's approach. More recent work suggests that the involvement of d orbitals is minimal.
Hybridisation is a concept from valence bond theory where the wave functions of atomic orbitals are "mixed" to create new orbitals, so-called hybrid orbitals. These point in very sensible directions structurally, sp, linear 1800, sp2 planar 1200, sp3 tetrahedral 109.50. This then fitted with the idea of electron pairs that would sit between nuclei.
Krypton is a noble gas and hence has stable electronic configuration. Its valence shell configuration is 4s2 4p6 . Therefore, it has 1-s and 3-p full orbitals in its valence shell.
Its the s and p orbitals
I suspect the word you're looking for is "degenerate."
All noble gases have completely filled orbitals. Helium has two valence electrons and its s-orbital is full and is stable. Other noble gases have completely fill p-orbitals as the valence orbitals.