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What is the ideal dc value of output signal when there is no input signal in class b amplifier?
ArunNath
A: If the input is zero the desire output is zero no matter what class it is.
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∙ 13y ago
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Why transformer is not called an amplifier?
In an ideal transformer the power in equals the power out there is no gain. In an ideal amplifier the power out equals the Gain *Power In. An ideal transformer transforms energy at a ratio of its windings. For example an ideal 1:10 ratio transformer (step up) would convert a 10Volt input at 10amps to a 100Volt output at 1Amp. Or conversely an ideal 10:1 ratio transformer (step down) would convert a 10Volt 10Amp input into a 1Volt 100Amp output. Since Power = Voltage * Current we can see the power in equals the power out in an ideal transformer. In an ideal amplifier the power out is greater than the power in. This is defined as the gain of the amplifier. An ideal amplifier with a Voltage gain of 10 would take a 1Volt 1amp signal and amplify it into a 10Volt 1 amp signal. An ideal amplifier with a Current gain of 10 would take a 1Volt 1Amp signal and amplify it into a 1Volt 10 amp signal. Since Power = Voltage * current we can see the power in is less than the power out showing a gain in power.
What is common mode output voltage?
I assume you're referring to an amplifier circuit. In a differential amplifier, there are two inputs. The common mode output voltage is the output voltage that will result from the same voltage being applied to both inputs. Typically this is very low, as the common mode rejection ratio (CMRR) is very high in a differential amplifier. This is an ideal characteristic (high CMRR) as it means unwanted noise will not be amplified and potentially squelch out the desired signal; this is why a differential amplifier is used in high quality sound equipment. Three wires are used - a ground, and two signal wires that are opposite each other. Noise will inherently "hop on" the signal wires, but as they are close to one another, it is likely the noise will be nearly the same magnitude and sign on each wire. Since the amplifier CMRR is high, this noise does not propogate through the amplifier, while the original signal is amplified.
What is common mode voltage?
I assume you're referring to an amplifier circuit. In a differential amplifier, there are two inputs. The common mode output voltage is the output voltage that will result from the same voltage being applied to both inputs. Typically this is very low, as the common mode rejection ratio (CMRR) is very high in a differential amplifier. This is an ideal characteristic (high CMRR) as it means unwanted noise will not be amplified and potentially squelch out the desired signal; this is why a differential amplifier is used in high quality sound equipment. Three wires are used - a ground, and two signal wires that are opposite each other. Noise will inherently "hop on" the signal wires, but as they are close to one another, it is likely the noise will be nearly the same magnitude and sign on each wire. Since the amplifier CMRR is high, this noise does not propogate through the amplifier, while the original signal is amplified.
Common-mode rejection ratio of an ideal amplifier?
The common mode rejection ratio of an ideal amplifier is infinity.
What is an ideal size for a car amplifier?
The ideal size amplifier for a car is between 80 and 100 watts, otherwise if the consumer wanted more sound or more amps the amplifier must be larger watts capacity.
Why input resistance of voltage amplifier is infinity?
For the successful amplification of the input signal the opamp should have ideally infinite input impedance . It should act like a buffer amplifierBUFFER amplifier--------------------->1.input impedance infinity2.output impedance zerothe reason is thatAny signal source will have source impedancefor the signal not to get lost and dropped across source impedance we ideally insert infinite impedance in series with it which makes the whole drop across the infinite impedance but not across the sourcesimilarly at the output zero impedance is used where in no part of the signal should be left behind in the op amp as a drop
What is the instantaneous sampling?
Instantaneous sampling is one method used for sampling a continuous time signal into discrete time signal. This method is called as ideal or impulse sampling. In this method, we multiply a impulse function with the continuous time signal to be sampled. The output is instantaneously sampled signal.
Which statement is true about the ideal mechanical advantage of a third-class lever?
mechanical advantage is the output force divided by the input force
Distinguish between op amp and differential amplifier?
Look up "op amp" on wikipedia, there is a good drawing near the bottom right. An op amp contains a differential amplifier as the first stage, but has multiple following stages that provide amplifier near ideal characteristics of high input resistance and low output resistance (it can drive more current than a single dif amplifier stage).
Why the input impedence of op-Amp is very high?
An ideal amplifier will have a very high input resistance, and low output resistance. This is so it doesn't "load" the input circuitry, and can drive output circuitry. Say you hooked an op amp up to a microphone that kicked out 100mV unloaded. If you shorted out the microphone, the output would approach 0mV (very low resistance load). If you connected a very high resistance load instead, the output would remain close to 100mV. As the load becomes a smaller resistance/bigger load, the output voltage will decrease until it is no longer useful. This is because the microphone has an internal resistance that remains constant while you're varying the attached load. The voltage drop across the internal resistance will increase as current output increases, causing less of a signal to be delivered to the amplifier.
What is the equation for ideal mechanical?
The equation for ideal mechanical advantage is: Output force/input force, Or input distance/ output distance.
How you differentiate amplifier and transformer?
A big difference. A transformer converts power into more useful means of transportation or matching to the end results.Pincoming = IPVP = Poutgoing = ISVS.giving the ideal transformer equationVs/VP= Ns/NP=IP/Isthen as the outgoing voltage of the transformer increase, the outgoing current will decrease. An amplifier adds power. For example, voltage amplifier add voltage (amplify) independent the amplifier current.
