A primitive to e^(x^(1/3)) is (e^(x^(1/3)))*(6-6x^(1/3)+3x^(2/3))
replace square root o x with t.
better place to ask would be yahoo answers
(e^x)^8 can be written as e^(8*x), so the integral of e^(8*x) = (e^(8*x))/8 or e8x/ 8, then of course you have to add a constant, C.
This integral cannot be performed analytically. Ony when the integral is taken from 0 to infinity can it be computed by squaring the integral and applying a change of variable (switching to polar coordinates). if desired I could show how to do this.
2 is the cube root of eight
2 = Cube Root of Eight
Cube root is the same as to the power of a third; when multiplying/dividing powers of a number add/subtract the powers; when a power is to another power, multiply the powers; as it is all e to some power: e³/(e²)^(1/3) × e^13 = e³/e^(2/3) × e^13 = e^(3 - 2/3 + 13) = e^(15 1/3) = e^(46/3) Which can also be expressed as "the cube root of (e to the power 46)" or "(the cube root of e) to the power 46".
The integral would be 10e(1/10)x+c
The square root of 16 is 4 and 4 cubed is 16x4=64
The square root of any number which is not a perfect square;The cube root of any number which is not a perfect cube;Pi, the circular constant.e, the natural logarithm base number.
integral of e to the power -x is -e to the power -x
(ex)3=e3x, so int[(ex)3dx]=int[e3xdx]=e3x/3 the integral ex^3 involves a complex function useful only to integrations such as this known as the exponential integral, or En(x). The integral is:-(1/3)x*E2/3(-x3). To solve this integral, and for more information on the exponential integral, go to http://integrals.wolfram.com/index.jsp?expr=e^(x^3)&random=false
The volume of a cube would be cubing an edge, or e^3, or e*e*e. Either way, you get the volume of a cube.
I'm not sure if you mean e^x + 17 or e^(x+17) so we'll do both. First, the integral of e^x + 17 because these terms are being added you can integrate them separately: integral((e^x)dx) + integral(17dx) integral of e^x is just e^x + C Integral of 17 is 17x + C, so we get: e^x + 17x + C Second, the integral of e^(x+17) we know how to integrate the form e^u, so just do a u substitution u=x+17 du=dx so we get integral((e^u)du)=e^u + C resubstitute for u and get e^(x+17) + C
The antiderivative, or indefinite integral, of ex, is ex + C.
C = k*a*d*e^3/sqrt(m) where k is a constant.
I'm pretty sure the answer is: C= de3k/ √m (C equals d times e cubed times k, divided by the square root of m).
e raised to the 0 power is 1
The root is the main directory. If your SD card has the drive letter E, then the root directory would be "E:" "E:\foldername" would not be the root.
Writing equations in questions is problematic - some symbols regularly get eliminated.The integral of e to the power x is: e to the power x + C If your expression contains no variables, for example e times e, or e to the power e, then the entire expression is a constant; in this case, the integral is this constant times x + C.
Use integration by parts. integral of xe^xdx =xe^x-integral of e^xdx. This is xe^x-e^x +C. Check by differentiating. We get x(e^x)+e^x(1)-e^x, which equals xe^x. That's it!
epi = 23.140692632779. pie = 22.459157718361. Thus, epi is greater.
Michael E Lord has written: 'Validation of an invariant embedding method for Fredholm integral equations' -- subject(s): Invariant imbedding, Numerical solutions, Integral equations
E was born and raised in Union,Kentucky
Square root of 2, square root of 3, square root of 5... actually the square root of any number that is not a perfect square.Cubic root of 2, cubic root of 3... again, the cubic root of any number that is not a perfect cube.Pi (about 3.1416)e (about 2.718)Trigonometric functions, for most values of the domainLogarithm and antilogarithms, for most values of the domainMost expressions that include any of the above.