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Chemistry

What is the ka of the first ionization of h3po4 if you initially had 0.58 m of phosphoric acid and your pH at equilibrium is 3?

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11/19/2014

[H+] = 10 raised to the -pH, or 10 raised to -3, which equals .001. Then Ka = [H+] squared / Molarity of the solution, which equals 1.72 E(-6).