Math and Arithmetic
Physics
Energy

What is the kinetic energy of a 60 grain bullet traveling at 3000 feet per second?

Answer

Wiki User
05/30/2009

60 grains = 0.003888 kg 3000 feet per second = 914.4 m/s Kinetic Energy = 0.5 x Mass x Velocity^2 KE = 0.5 x 0.003888 x 914.4^2 = 1625.43158784 Joules