If: y = 17-3x and y = x^2+2x-7
Then: x^2+2x-7 = 17-3x => x^2+5x-24 = 0
Solving the quadratic equation: x = -8 and x = 3
Points of intersection with the parabola: (-8, 41) and (3, 8)
Length of line: square root of [(-8-3)^2+(41-8)^2] = 34.785 to 3 d.p.
Yes.
Y = X2 forms a parabola
(-3, -5)
y=6x² is already solved. the parabola will touch the x-axis at x=0.
A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.
It is the equation of a parabola.
Yes.
Y = X2 forms a parabola
A U shaped parabola
(-3, -5)
The minimum value of the parabola is at the point (-1/3, -4/3)
7
it will form a parabola on the graph with the vertex at point (0,0) and points at (1,1), (-1,1), (2,4), (-2,4)......
y=6x² is already solved. the parabola will touch the x-axis at x=0.
The solution comprises every point on a parabola which is symmetric about the y axis and has its apex at (0,1).
A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.
16 = 16.0. ( < to the left I was showing what 16 equals in decimal form ). So there for you answer will be 16.0