If a 27 ft tall pole casts an 18 foot shadow, a 63 ft tall pole casts an x foot shadow.
Put 27/18 and 63/x.
Cross multiply, get 27x=1134
Divide by 27 on both sides, a 63 foot tall pole casts a 42 foot long shadow.
That depends on the height of the yardstick whose height has not been given.
Depends what time of day it is ... how high the sun is. It keeps changing all day. No shadow at all at night.
You have two similar triangles with one side the tree, and another the shadow Using the side with the tree, the ratio of the length of the triangles can be found: the triangles are in the ratio of 24 : 40 Thus divide the shadow of the 40ft tree by 40 to find out the length of shadow per foot of tree, and multiply this by 24 to find the length of the shadow of the 24 ft tree. This can be done by using the ratio as a fraction 24/40: → the shadow of the 24 ft tree is 16 ft × 24/40 = 9.6 ft
Using Pythagoras' theorem it is 30 feet
Answer is 14 feet
The lenght of the shadow will be 12.6 ft
Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.
27.3 feet
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
17.45 feet.
Using trigonometry its height is 12 feet
10.'384615' (recurring decimals) feet
15 feet high
121.3yd
That is an impossible question it could be any size the length of the shadow is dictated by the angle if the light source.
63 feet
A 1 foot shadow I think.