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What is the mass of 2.00 mol h2o?

Updated: 8/10/2023
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11y ago

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0.8 moles HNO3 (63.018 grams/1 mole HNO3)

= 50 grams nitric acid

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11y ago
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9y ago

The mass of 3.80 mol H2O would be 0.2375. This is a math problem.

No, chemistry.

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12y ago

0.80molesN2*(3molesH2/1moleN2)=2.40 moles

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7y ago

The mass of 0.5 moles of H2 is 2 g.

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6y ago

2.00 mol He x 4.00 g/mol = 8.00 grams

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14y ago

1.6 g

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11y ago

36g

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Q: What is the mass of 2.00 mol h2o?
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Related questions

What is the gram formula mass for H2O?

H2O's molar mass is 18 g/mol.


What is the molcular mass of water?

Molar mass of H2O = 18.01528 g/mol


What is the mass of 200 moles of Fe?

200 (mol) * 56.0 (g/mol) = 11,200.0 grams


What is the mass (in grams) of 1 mol H2O?

You calculate it by using Avogadro's number: 6.022 x10 23 which is one mole of substance. 1.00 x 1024 divided by 6.022 x 1023 = 10 divided by 6.022 = 1.661 mol H2O Use the molar mass of water (18.02 g mol-1) to get to the mass in grams. 18.02 g x 1.661 mol = 29.93 g H2O


What is the molar mass of H2O to the nearest whole number?

18g/mol


The mass percent of water in a hydrate of mncl2 is 36.41 percent what is the fomular of the hydrate?

36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate


What is 1 mol of H2O in grams?

in order to find the mass of H20 you need the molar mass which is 18.01g/mol and to calculate the mass you just multiply by the number of moles. 18.01 * .20 = 3.60g


Find the mass in grams of 1.54 moles of H2O?

1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams


What is the value of x When a 1.63 g sample of MgCl2xH2O is heated to remove all water a mass of 0.762 g remains?

You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O


How many grams of water are produced by reacting 15.8 g H2 with excess oxygen?

24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O


How many grams of copper sulfate would you heat to produce 29.8g of water?

29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O


How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?

29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O