For this you need the atomic (molecular) mass of CaCO3. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel. CaCO3= 100.1 grams
2.50 moles CaCO3 × (100.1 grams) = 250.25 grams CaCO3
Mass = mol x molar Mass = 2.5mol x 40g/mol = 100g
Well ... Mass = mol x molar Mass = 2.5mol x 40g/mol = 100g Hope this helps :)
2.50 moles Ca (40.08 grams/1 mole Ca)
= 100 grams calcium.
1400 grams
234 grams :)
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
The formula given shows that each formula unit or mole contains one calcium atom; therefore, 2.5 moles of calcium chloride contains 2.5 moles of calcium atoms.
2,8 moles of calcium carbonate have 240,208 g.
1400 grams
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
42,5 grams calcium is equivalent to 1,06 moles.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
The number of moles of calcium carbonate are 3.5 moles. , there are 1 mole of calcium (Ca) atom, 1 mole of carbon (C) atom and 3 moles of oxygen (O) atoms.
No. of moles=wt. of substance/molecular wt. hence, wt. of substance= 2.38*100=238
120 grams of calcium contain 2,994 moles.
This is a mass stoichiometry problem. Start with the balanced equation: CaCO3 --> CaO + CO2. Do a conversion from 50g CaO to moles: 56g/1mol=50g/x, x=.9 moles. The equation is balanced as written, with all coefficients understood to be 1. So: .9 moles CaO means .9 moles CaCO3. Do another conversion from moles to grams: 100g/1mol=x/.9 moles. Solve for x to get 90 grams. (56g=molar mass of calcium oxide; 100g=molar mass of calcium carbonate.)
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
The molar mass of calcium is 40,078 g.40,078 g------------------------1 mol8 g---------------------------------xx = 8/40,078 = 0,2 moles