4 times the Atomic Mass of hydrogen plus the atomic mass of carbon, or (4 X 1.008) + 12.011, or 16.043.
Relative molecular mass is obtained.It is about 17
CH4 is a neutral molecule, it does not carry a charge.
1 C = 1 x 12.01 (mass of carbon) = 12.01 g/mol
4 H = 4 x 1.008 (mass of hydrogen) = 4.032 g/mol
12.01 g/mol C + 4.032 g/mol H = 16.042 g/mol CH4
hope that helped
16. Carbon has a molecular mass of 12, and hydrogen has a molecular mass of 1. 12 + 4(1) = 16.
Mass of one mole is 16.So total mass is 32g
Divide 96 by molecular mass.So the answer is 6mol
Molar mass:O2 32 g/molCH4 16 g/molReaction:CH4 + 2 O2 --> CO2 + 2H2OCalculus1 mol CH4 with 2 moles O2Given: 24 g CH4 equals 24/16 = 1.5 mol CH4this will need 2 * 1.5 moles O2 = 3.0 mol O23.0 mol O2 equals 3.0 * 32 = 96 g O2
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
Divide 96 by molecular mass.So the answer is 6mol
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
There are 0.75 moles in it.You have to devide 12 by molecular mass
This mass is 6,416 g.
Molar mass:O2 32 g/molCH4 16 g/molReaction:CH4 + 2 O2 --> CO2 + 2H2OCalculus1 mol CH4 with 2 moles O2Given: 24 g CH4 equals 24/16 = 1.5 mol CH4this will need 2 * 1.5 moles O2 = 3.0 mol O23.0 mol O2 equals 3.0 * 32 = 96 g O2
Mass of 4 mole CO2 , this is 4 * (12 + 2*16) = 176 grams
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
CH4 + 2 H2O = 3 H2 + CO2 8 moles CH4 produce 8 x 3 moles H2, which is 24.
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================
One molecule has four H atoms.So two moles have 8 moles