Top Answer

The median is the value that is in the middle of the number sequence. If there are two values in the middle, you find the median by averaging the two middle numbers. So by taking 2+3 then dividing that by 2 you get 2.5

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0it is 3

3

mean= 2, mode= 1 and 3, median= 3, and range= 2

median is like medium so, isn't it lke 1.5 like half way between 1 and 2 bacause there is an even amout of numbers.

2.5 is the median

1

A median is the middle of a series of numbers, so the answer is 2.

4.5

A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!

The median of 00000201 is 0 The way to figure is out is: 1. put them into ascending order (lowest to highest) 2. cross off the each end number like this : 0 0 0 0 0 0 1 2 3. keep going : 0 0 0 0 0 0 1 2 4. if there is one number left in the middle, that's the answer, but if there's two, you divide them: so in this case, is: 0 / 0

If you line them up from least to greatest, you have: 1 1 2 3 5 Then, you take the middle number, which in this case is 2, and that is your median.

2

The median is 4.

There is only one median in a set of values. If it is an odd amount of values, the median is the middle number. If there is an even amount of numbers, the median is the value halfway between the two middle numbers. So, in 1, 2, 3; the median is 2. In 1, 2, 3, 4; the median is 2.5, as that is halfway between 2 and 3.

Median: 3 Mode: 1 Range: 6

yes. for example 1 2 2 and 3. Median is (2+2)/2=2

The answer is 3

3

2 or 3

For an odd number of data values, the median is the middle number, the [(n+1)/2]th numberi.e. for 7 data values, (7 +1)/ 2 = 4, and the 4th is the middle value, or median.*For an even number of values, the median is the mean of the two middle numbers,i.e. one-half the sum of the two middle values (add n/2nd value and n/2+1st values and divide by 2).Examples:Median of 1, 3, 2 reordered as 1, 2, 3 = median 2Median of 6, 5, 3, 1 reordered as 1, 3, 5, 6 = median 4 (3+5 divided by 2)

2.5

You are right. 1 is the median.The median of a set of data is found by arranging the data in increasing or decreasing order. So, we can arrange the items: 0, 1, 1, 1, 4, 4If the number of items of data is even, as it is in this case, then the median is the average (or mean) of the two middle numbers. So, the median is (1 + 1)/2 = 2/2 = 1If the number of items of data is odd, then the median is the middle number in the ordered set. For example the median of the data 1, 3, 3, 5, 6, 8, 9 is 5, because 5 is in the middle.It is also the mode. The mode of a set of data is the one item of data that occurs most often. 1 has the highest number of frequency in this sample. Thus 1 is the mode also.

The median is the middle value. 2 , 2 , 3 , 4 , 5 Median = 3

E|----------------|-------0-1-0----|----------------|--------1-0-----|--| B|--0-1-----0-1--|--0-1--------1-|------0-1-------|------1----1---|--| G|0-------0------|0--------------2|0-------------0-|-----2-------2-|0-| D|----------------|-----------------|----------------|3--3------------|--| A|----------------|-----------------|----------------|-----------------|--| E|----------------|-----------------|----------------|-----------------|--| E|----3-1---------|-----------------0-|1---------------| B|--------1-------|-----------3-1-----|----------------| G|----------0-----|0-------0----------|----------------| D|------------2-3|----2-3------------|----------------| A|----------------|--------------------|----------------| E|----------------|--------------------|----------------| E|----------------|--------0-1-0----|----------------|-------1-0-----|--| B|--0-1-----0-1-|---0-1-------1--|------0-1-------|------1----1---|--| G|0-------0------|-0--------------2|0------------0-|-----2-------2-|0-| D|----------------|------------------|----------------|3--3-----------|--| A|----------------|------------------|----------------|----------------|--| E|----------------|------------------|----------------|----------------|--|

It SHOULD be counted. The median is the number halfway between 2 and 3 ie 2.5 and the range is 5.

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