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4 mol over 0.800 kg

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11y ago
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12y ago

Molarity = moles of solute/Liters of solution

So, we need moles of glucose.

4 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.02220 moles glucose

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Molarity = 0.02220 moles C6H12O6/1 Liter

= 0.02 M glucose

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9y ago

The molarity of a solution is 0.400 mol divided by 4.00 kg which equals 0.100 mol/kg solvent which equals 0.100 m.

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12y ago

The molality of a solution is the moles of solute divided by the mass of the solvent (in kg):

molality = mass/kg So, molality = 4.0 moles / 3.2 kg = 1.25 moles/kg

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8y ago

The molality of this solution is 1,905; to calculate the molarity you need the density of the solution.

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6y ago

4 mol/0.800 kg

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7y ago

The molality is 5.

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6y ago

The molality is 5.

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Q: What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
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