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# What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?

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###### Wiki User

Molarity = moles of solute/Liters of solution

( get moles of HNO3 and 300 ml = 0.300 Liters )

0.31 grams Nitric acid (1 mole HNO3/63.018 grams)

= 0.004919 moles HNO3

Molarity = 0.004919 moles HNO3/0.300 Liters

= 0.0164 M HNO3

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