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# What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?

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Molarity = moles of solute/Liters of solution

( get moles of HNO3 and 300 ml = 0.300 Liters )

0.31 grams Nitric acid (1 mole HNO3/63.018 grams)

= 0.004919 moles HNO3

Molarity = 0.004919 moles HNO3/0.300 Liters

= 0.0164 M HNO3

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## Related Questions   NaF has an atomic mass of 42, therefore if you dissolve 42 grams (1 mole) of it in 2 liters of water you get a molarity of 0.5 moles/Liter. 31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity  Increasing the amount of the solute in the solution the molarity and the density of this solution increases.  Molarity = moles of solute/volume of solution 2.24 grams NaOH (1mol/33.998g) = 0.0659 moles NaOH/0.5 liters = 0.132 Molarity of NaOH  Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl Molarity = moles of solute/Liters of solution need to find moles NH3 16.7 grams NH3 (1 mole NH3/17.034 grams) = 0.9804 moles NH3 --------------------------------now Molarity = 0.9804 moles NH3/1.50 Liters = 0.654 M -------------  It depends what the solute is. There is no way to determine the molarity without knowing that piece of information. Molarity = moles of solute/Liters of solution Get moles of Fe2O3 160.0 grams Fe2O3 (1 mole Fe2O3/159.7 grams) = 1.0 mole Molarity = 1.0 mole/1.0 liters = 1.0 M Fe2O3 Need moles HCl first.9.63 grams HCl (1 mole HCl/36.458 grams) = 0.2641 moles HClMolarity = moles of solute/Liters of solutionMolarity = 0.2641 moles HCl/1.5 Liters= 0.176 M HCl solution================= Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution -------------------------------- Molarity is defined as grams of solute dissolved in 1 liter of solution and molality is defined as grams of solute dissolvd in 1Kg of solvent Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1 Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 --------------------- Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose --------------------------- Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity. Molarity = moles of solute/Liters of solution Without the solute name the mass ( 8 grams ) does no good. Mass of solute (1 mole/molar mass of solute) = moles solute ----------------------then use Molarity equation. ( remember convert to liters ) Magnesium sulfide react with water.This is not solubilty and molarity cannot be applied. Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity Having the Molarity, concentration, helps. Molarity = moles of solute ( gotten from the grams put into solution ) divided by Liters of solution. Then. - log( Molarity of compound ) = pH ====( if basic subtract from 14 )

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