Find moles potassium iodide first.
2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KI
Molarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )
Molarity = 0.01452 moles KI/0.1 Liters
= 0.145 M KI solution
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
The molarity of KNO3 is 0,058.
This value is 0,0164 M.
Molarity = moles of solute/volume of solution 2.24 grams NaOH (1mol/33.998g) = 0.0659 moles NaOH/0.5 liters = 0.132 Molarity of NaOH
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
The molarity is 0,33.
Of which concentration do you enquire?
The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.
.62 M is the molarity of the solution made by dissolving 22.4 g of LiClO4 3H2O in 225 mL of water.
Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY
Molarity=Moles of solute/Liters of solution1.350 g KOH = 0.02406 mol KOH0.02406 mol/0.2500 L =0.09624 M of KOH
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
That completely depends on the molarity of the solution.
You prepare a solution by dissolving a known mass of solute (often a solid) into a specific amount of a solvent. One of the most common ways to express the concentration of the solution is M or molarity, which is moles of solute per liter of solution.
The molarity is 2 (or 80 g/L).
15.8/180 is 0.08777778 moles in 169ml. divide by 169, x 1000 (per litre) is 0.5194M
Molarity means moles per litre. this means if you divide moles by the volume in litres, you get the molarity. 3.09/1.5 = 2.06 molar.
Get moles sodium sulfate first.15.5 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.1091 moles Na2SO4Now,Molarity = moles of solute/ Liters of solution ( 35 ml = 0.035 Liters )Molarity = 0.1091 moles Na2SO4/0.035 Liters= 3.1 M Na2SO4 solution==================
The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
The moLaRity of this solution ie 2 mol/L or 2M KI (it is a 'two molair potassium iodide' solution)
molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L
The morality of the solution is roughly 2.5 mols per liter.
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