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Answered 2012-05-07 00:35:38

Find moles potassium iodide first.

2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KI

Molarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )

Molarity = 0.01452 moles KI/0.1 Liters

= 0.145 M KI solution

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what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?




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The moLaRity of this solution ie 2 mol/L or 2M KI (it is a 'two molair potassium iodide' solution)


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