Chemistry

# What is the molarity of a solution prepared by dissolving 7 grams of NaCL in enough water to make a 450.0 mL solution?

Molarity = moles solute/liter solution
moles solute = 7 g NaCl x 1 mol NaCl/58 g NaCl = 0.12 moles NaCl
liters of solution = 450.0 ml x 1 L/1000 ml = 0.450 liters
molarity = 0.12 moles/0.450 liters = 0.268 M = 0.3 M (one sig fig)

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to make the solution basic enough so that NH be prepared for Fmoc protection

Molarity (concentration ) = moles of solute/Liters of solution 250.0 ml = 0.250 liters 2.431 grams H2C2O4 * 2H2O ( 1mole cpd/ 126.068 grams) = 0.01928 moles H2C2O4 * 2H2O Molarity = 0.01928 moles cpd/0.250 liters = 0.07712 Molarity

The molarity is 0.001255. Should you really be asking an AP Chem question on Wiki Answers, anyways?

[117(g NaCl) / 58.5(g NaCl/mol NaCl)] / 40.0(L solution) = [117/58.5]/40.0 = 2.00(mol NaCl) / 40.0(L) = 0.0500 mol NaCl / L solution = 0.0500 M

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