What is the molarity of a solution that contains 125 g NaCl dissolved in 4.00 L of solution?

Answer 1

The Molarity of the solution is .901

Answer 2

First off you have to divide by 274 and multiply by 1000 to get the grams in a litre. This gives you 456.2g per litre. Then you divide by the molecular mass. 456.2/58.443 which is 7.8 molar.

Answer 3

Molarity is moles per litre, however we have 4 litres. So we have to divide 125 by 4 first. 125/4 is 31.25 grams. The molecular weight of NaCl is 58.443g/mol so the overall molarity is 0.53471 molar.

Answer 4

I assume you mean 174 grams NaCl. Be careful with units, decimal points and amounts as we are not mind readers here and I could be wrong about this assumption. Regardless, need moles NaCl first.

174 grams NaCl (1 mole NaCl/58.44 grams)

= 2.977 moles NaCl

=================now,

Molarity = moles of solute/Liters of solution

Molarity = 2.977 moles NaCl/4.00 Liters

= 0.744 M NaCl solution

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Answer 5

The gram formula mass (for an ionically bonded compound such as NaCl, the counterpart to a gram mole for covalently bonded compounds) is 58.44. Therefore, 125 g of NaCl constitutes 125/58.44 or about 2.1389 gram "moles". Since molarity is defined as the ratio of moles of solute dissolved to total volume of solution, the given solution is 0.535, to the justified number of significant digits.

Answer 6

125g NaCl x 1 mol NaCl / 58.44 NaCl= 2.13894 mol / 4.00 L = 0.535 M

Answer 7

Molarity = moles of solute/volume of solution

so, 125 grams of NaCl (1mol NaCl/58.44 grams NaCl)

= 2.1389 moles NaCl/400 Liters

= 0.00535 M NaCl

Answer 8

The Molarity of the solution is .901