Molarity = moles of solute/volume of solution
so, 125 grams of NaCl (1mol NaCl/58.44 grams NaCl)
= 2.1389 moles NaCl/400 Liters
= 0.00535 M NaCl
125g NaCl x 1 mol NaCl / 58.44 NaCl= 2.13894 mol / 4.00 L = 0.535 M
Molarity is moles per litre, however we have 4 litres. So we have to divide 125 by 4 first. 125/4 is 31.25 grams. The molecular weight of NaCl is 58.443g/mol so the overall molarity is 0.53471 molar.
The gram formula mass (for an ionically bonded compound such as NaCl, the counterpart to a gram mole for covalently bonded compounds) is 58.44. Therefore, 125 g of NaCl constitutes 125/58.44 or about 2.1389 gram "moles". Since molarity is defined as the ratio of moles of solute dissolved to total volume of solution, the given solution is 0.535, to the justified number of significant digits.
First off you have to divide by 274 and multiply by 1000 to get the grams in a litre. This gives you 456.2g per litre. Then you divide by the molecular mass. 456.2/58.443 which is 7.8 molar.
sucrose is c12h22o11 -- molar mass - 12x12 + 22x1 + 11x16 = 342 g/mole (125 / 342) / 3.5 = 0.1044 M
The molarity of a solution made by dissolving 23,4 g of sodium sulphate in enough water to make up a 125 mL solution is 1,318.
The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution
Molarity = moles of solute/volume of solution 0.500 M KOH = moles KOH/125 ml 62.5 millimoles, or to answer the question precisely, 0.0625 moles KOH
The percentage of a 1 to 125 solution is simply 1/125 or 0.008 or 0.8%.
Firstly place 100 to 150 mg of aspirin into a 125 ml conical flask. Next proceed to mix in 15 ml of 95% ethanol solution and add 2 drops of phenolphthalein indicator. Then use the titration method to mix this solution against a standard solution of sodium hydroxide from a burette. Using the value obtained from the titration calculate the molarity of the aspirin. Then calculate the ratio of the observed molarity of aspirin with its theoretical molarity and finally multiply this ratio with 100 to obtain the percentage purity of the aspirin sample.
Molarity = moles of solute/volume of solution 1.50 M = X Moles/125ml = 187.5 millimoles, which is 0.1875 moles The molar mass of CaCl2 = 110.98 grams 0.1875 moles CaCl2 (110.98g/1mol) = 20.8 grams needed
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
Y^2 = 125 Y = +/- sqrt(125) Y = +/- 5sqrt(5)
You need to know the gram molecular mass (in this instance, since sodium chloride is an ionically bonded compound and does not have moles in the strictest sense, more properly the gram formula unit mass) of sodium chloride, which is 58.44. The number of grams required may be calculated as set forth below. By definition, a 0.05M solution contains 0.05 moles of solute (sodium chloride in this instance) per liter of solution, and there are 1000 ml per liter. Therefore, the number of moles required for the specified amount of 0.05M solution is 0.05(125/1000) or 0.00625. The amount of sodium chloride required is therefore 0.00625(58.44) or 0.4 grams, to the justified number of significant digits, which is limited by the fact that the molar concentration stated has only one significant digit. If 0.05 were interpreted as having at least three significant digits, then the answer would be 0.3652 grams.
solution:125 lb. ( 1kg/ 2.2lb.)cancel out the same units=56.818182kg in 125lb.ur welcum!-meedah-chan125 pounds = 56.7 kilograms.
Simply divide 125 by 14.3. The answer is 8.74.
Are you sure you mean 0.211 m not 0.211 M Is the concentration molality or molarity? If 55 ml of a 0.211 m NaOH is diluted to a final volume of 125 ml what is the concentration of NaOH in the diluted solution?NaOH not NaHO the compound is Sodium hydroxide Molar mass of NaOH = 23 + 16+ 1 = 40 0.211 moles of NaOH = 0.211 * 40 = 8.44 grams of NaOH per liter of solution 55 ml = 0.055 Liter 8.44 grams of NaOH per liter of solution * 0.055 liter = 0.4642 g of NaOH Moles of NaOH = 8.44 ÷ 40 = 0.211 moles 0.211 moles of NaOH in 125 ml = 0.211 moles ÷ 0.125 L = 1.688 m
You can prepare 250 mL of a 2,5 % solution.
What's wrong with it, The simple solution is to fix it :)
One Lemon Drop Martini contains 125 calories.
no Yes. On NutritionData.com, 8 ounces of yogurt contains from 125 to 160 mg of sodium.
The "8.00 M Ba(OH)2" means 1 L of that solution contains 8.00 mol Ba(OH)2. 125 mL x 1 L x 8.00 mol Ba(OH)2 = 1.00 mol Ba(OH)2 ...........1000 mL ........ 1 L
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The general formula of linear alkanes is CnH2n+2. If an alkane with 125 carbons exist (I don't know) the chemical formula will be C125H252 and the name pentacosehectane.