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I assume you mean 174 grams NaCl. Be careful with units, decimal points and amounts as we are not mind readers here and I could be wrong about this assumption. Regardless, need moles NaCl first.

174 grams NaCl (1 mole NaCl/58.44 grams)

= 2.977 moles NaCl

=================now,

Molarity = moles of solute/Liters of solution

Molarity = 2.977 moles NaCl/4.00 Liters

= 0.744 M NaCl solution

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Q: What is the molarity of a solution that contains 174 NaCl in 4.00L solution?

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The answer is 0,514 mol.

Molarity = moles of solute/volume of solution so, 125 grams of NaCl (1mol NaCl/58.44 grams NaCl) = 2.1389 moles NaCl/400 Liters = 0.00535 M NaCl

molarity of 5% NaCl solution would be 1.25M.

The molarity is 0,149.

Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------

125g NaCl x 1 mol NaCl / 58.44 NaCl= 2.13894 mol / 4.00 L = 0.535 M

Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========

What is the molarity of a solution containing 325 g of NaCl dissolved in 750.ml of solution?

The molarity is 6.

Molarity=Moles/Liter.. the answer is .057L or .057mL

1.7M

Molarity = moles of solute/volume of solution Find moles NaCl 55 grams NaCl (1mol NaCl/58.44 grams) = 0.941 moles NaCl Molarity = 0.941 moles NaCl/35 Liters = 0.027 Molarity NaCl ( sounds reasonable as 55 grams is not much in 35 Liters of water, which would be about 17.5 2 liter sodas )

1.3g

Molarity = moles of solute/Liters of solution Find moles NaCl 9 grams NaCl (1 mole NaCl/58.44 grams) = 0.154 moles NaCl Molarity = 0.154 moles NaCl/1 Liter = 0.2 M sodium chloride -------------------------------

Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------

Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------

I suppose that this situation is not possible.

0.9% NaCl solution is a solution that contains 0.9 grams of NaCl for every 100mL of the solution.

Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============

Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------

Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------

Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------

Molarity = moles of solute/Liters of solution 3.45 M NaCl = moles NaCl/5 liters = 17.25 moles

Given: 0.5 g NaCl; 0.05 L of solution.1) Find the molar mass of NaCl.(22.99) + (35.45) = 58.44 g/mol of NaCl2) Convert grams of NaCl to moles of NaCl.(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl3) Use the molarity equation, M = mol / L, to solve for molarity (M).(0.00855578 mol NaCl / 0.05 L) = 0.17 M

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