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What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Wiki User
∙ 12y ago
Need moles MgCl2
75.0 grams MgCl2 (1 mole MgCl2/95.21 grams)
= 0.7877 mole MgCl2
================now,
Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters )
Molarity = 0.7877 moles MgCl2/0.5 Liters
= 1.58 M MgCl2 solution
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∙ 12y ago
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How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
What is the molarity of 80g magnesium chloride dissolved in 250ml of water?
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
How many grams of MgCl2 are needed to make 700.mL of a 1.4 M solution?
93,31 g MgCl2 are needed.
Why is MgCl2 added to a solution of EDTA?
to make the reaction and associated calculations more complicated
What mass in g of agcl is formed from the reaction of 75.0 ml of a 0.078 m agc2h3o2 solution with 55.0 ml of 0.109 m mgcl2 solution?
0.838g
How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
What is the molarity of 80g magnesium chloride dissolved in 250ml of water?
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
What is the molarity of 0.96 g MgCl2 in 0.500 L of solution?
The molar mass of MgCl2 is 95.21 g. Therefore 0.96 grams is 0.01008 mol of the substance. So the molarity of the solution is 5.04 x 10-3 M.
What is the molarity of0.73 g MgCl2 in 300 mL of solution?
Molarity = moles of solute/volume of solution. 0.73 grams MgCl2 (1mol/95.21g ) = 0.00767 moles/0.300 Liters ( to get M, not mM ) = 2.6 X 10^-2 M
If 5.25 g of MgCl2 is dissolved in 200.0 ml of solution calculate the concentration( molarity) of MgCl2, the magnesium ion, and the chlorine ion?
Atomic weight for Mg is 24.305, for Cl is 35.453. Molecular weight for MgCl2 is 24.305 + 2(35.453) = 95.211. Molarity for the MgCl2 solution made with 5.25 g of the salt diluted to 200 ml is, M = [5.25/95.211] x [1/0.200 liter] = 0.2757 Molar Assuming 100 % ionic dissociation, Molarity of Mg+2 is 0.2757 and for Cl- is twice, 0.5514
Does mgcl2 is an aqous solution?
yes mgcl2 is aqous solution
How many ML equal 17.5 MG?
1 mole of MgCl2=95.21 grams (found on the periodic table) 17.5 g of MgCl2(1mole of MgCl2/95.21g of MgCl2)=.184 moles of MgCl2(grams cancel out and rounded to 3 sig. figs) .184 moles of MgCl2 (1 Liter/2.5 moles of MgCl2)=0.735L of MgCl2 (moles cancel and rounded to 3 sig figs) 0.735 L of MgCl2(1000 milliLiters/1 Liter)=73.5 mL of MgCl2 and round the answer to 2 sig figs which equals 74 milliLitersof MgCl2
If you have 45 grams of MgCl2 and dissolved it in 0.5 L. Find the molarity of MgCl2?
45 g MgCl2 x 1 mole MgCl2/95.2 g /0.5 L = 0.9045 moles/L = 0.90 M (to 2 significant figures)
What is molarity of soultion containing 12.5g of Mgcl2 in 200 ml soultion?
MgCl2 Mg = 24.30 2Cl = 70.906 FW = 95.21 (Remember SigFigs) 12.5g ÷ 95g of MgCl2 = 0.131 moles of MgCl2 200mL = 0.200 L 0.131 moles of MgCl2 ÷ 0.200 L = 0.656 Molar Concentration
What is the different between magnesium chloride solution and magnesium chloride crystals?
MgCl2 solution is obtained when it is dissolved in water whereas when it is in crystalline form then it is known as MgCl2 crystall.
How many grams of MgCl2 are needed to make 700.mL of a 1.4 M solution?
93,31 g MgCl2 are needed.
What happens when you mixed the magnesium chloride solution with the sodium cabonate solution?
MgCl2 + Na2CO3 = 2NaCl + MgCO3
