I assume you mean 0.5 molar, but I'll go with what I'm given. If you have 500 molar of barium chloride, you will have 1000 molar of chloride ions as there are 2 chlorides for every 1 molecule of barium chloride. Having the 100ml there is irrelevant as you are talking about concentration and didn't ask for moles.
7.00 g baso4
89.3
0.67 M
100 g of the solution contains 11 g of sodium chloride
1.7M
7.00 g baso4
89.3
89.3
From 100 to 113 Deg C, barium chloride convert to anhydrous form.
0.67 M
One mole solution of sodium chloride makes 1000 millimole. So 0.1 mole solution of sodium chloride will have 100 millimole in the solution.
100 g of the solution contains 11 g of sodium chloride
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
You know because of solubility rules that LiCl disassociates 100% in water. So, knowing that molarity is equal to moles/liters Molarity LiCl = 1.97mol / 33.2 L Molarity = 0.059 M LiCl
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
Ammonium chloride dissociates 100% into ions in solution. The ammonium ions interact with the hydroxide ions from the water removing them from the solution. This increases the concentration of hydrogen ions, increasing the acidity of the solution. We say that a solution of ammonium chloride is acidic by hydrolysis.
Dissolve 100 mg sodium chloride in 1 L demineralized water.