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2 moles of aluminum to 3 moles of oxygen
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What is the mole ratio of air to methane gas in the cumbustion of methane?
If by "air" you mean oxygen, then the mole ratio can by found by balancing a reaction equation. CH4 + 202 -> CO2 + 2H2O The ratio is 1:2.
Will 27 grams of aluminium react completely with 24 grams of oxygen?
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5
What happens if 0.1 mole methane reacts with 0.1 mole oxygen gas?
Lets start with the reaction of methane fully reacting with oxygen: CH4 + 2 O2 --> CO2 + 2 H2O The ratio CH4:O2 is 1:2 So 0.1 mole of methane can potentially react with 0.2 mole of oxygen. Seeing as we only have 0.1 mole oxygen we know that we have excess of methane. Because of the lack of oxygen the methane can form carbonmonoxide (CO) instead of CO2. (if someone knows the composition of the final product, please add here. As far as i know, you cant predict the CO:CO2 ratio.)
What is the theoretical yield of aluminum oxide if 2.40 mole of aluminum metal is exposed to 2.10 mol of oxygen?
Balanced equation: 4Al(s) + 3O2(g) ==> 2Al2O3(s)2.40 mol Al ==> 1.2 moles Al2O3 (mole ratio of Al2O3 : Al is 2:4 or 1:2)2.10 mol O2 ==> 1.4 moles Al2O3 (mole ratio of Al2O3:O2 is 2:3)Therefore, Al is the limiting reactant.Theoretical yield will thus be 1.2 moles Al2O3. If you need mass, it is 1.2 moles x 102 g/mol = 122 g
How many atoms in a mole of aluminum III oxide?
Aluminium Oxide(Al2O3) has 2 moles of aluminum and 3 moles of oxygen. The total is 5 moles. One mole is 6.022 x 1023 atoms. Therefore, 5 moles = 30.110 x 1023 atoms
If the burning of the magnesium ribbon was out of control would it affect the mole ratio of oxygen to magnesium?
No. According to the law of definite proportions, the mole ratio will always be the same.
How much oxygen in grams will be required to react with 0.5 mole of aluminium?
Three atoms of oxygen are required to react with each two atoms of aluminum to form the most common product of reaction between oxygen and aluminum. Therefore, 0.75 mole of oxygen atoms will be required to react with 0.5 mole of aluminum atoms. The atomic weight of oxygen is 15.999; therefore, the mass will be (0.75)(15.999) = 12 grams of oxygen, to the maximum possibly justified number of significant digits.
What is the mole ratio of air to methane gas in the cumbustion of methane?
If by "air" you mean oxygen, then the mole ratio can by found by balancing a reaction equation. CH4 + 202 -> CO2 + 2H2O The ratio is 1:2.
How if the magnesuim is not polished would the reported mole ratio of oxygen to magnesium be too high too lowor unaffected?
the ratio of magnesium to oxygen is .29 : .18
What does al2o3 stand for?
Aluminum oxide has the molecular formula of Al2O3. It is composed of aluminum (Al) and oxygen (O) and is 102.0 grams per mole.
How does the experimental mole ratio compare with the theoretical mole ratio?
the experimental mole ratio has a bigger penis
Will 27 grams of aluminium react completely with 24 grams of oxygen?
Yes.Explanationary:27 g Al = 1.0 mole Al24 g = 1.5 mole O2 so this ratio (in mole) is 1:1.52Al + 3O2 --> Al2O3 so the balanced mole ratio is 2:3 or 1:1.5
The relative number of moles of hydrogen to moles of oxygen that react to form water represent what?
Mole Ratio
What happens if 0.1 mole methane reacts with 0.1 mole oxygen gas?
Lets start with the reaction of methane fully reacting with oxygen: CH4 + 2 O2 --> CO2 + 2 H2O The ratio CH4:O2 is 1:2 So 0.1 mole of methane can potentially react with 0.2 mole of oxygen. Seeing as we only have 0.1 mole oxygen we know that we have excess of methane. Because of the lack of oxygen the methane can form carbonmonoxide (CO) instead of CO2. (if someone knows the composition of the final product, please add here. As far as i know, you cant predict the CO:CO2 ratio.)
Use the mole ratio to determine the number of moles of carbon dioxide produced when 0.136 mole of 1-heptanol reacts with excess oxygen in a combustion reaction?
0.95 - 0.954
What is the theoretical yield of aluminum oxide if 2.40 mole of aluminum metal is exposed to 2.10 mol of oxygen?
Balanced equation: 4Al(s) + 3O2(g) ==> 2Al2O3(s)2.40 mol Al ==> 1.2 moles Al2O3 (mole ratio of Al2O3 : Al is 2:4 or 1:2)2.10 mol O2 ==> 1.4 moles Al2O3 (mole ratio of Al2O3:O2 is 2:3)Therefore, Al is the limiting reactant.Theoretical yield will thus be 1.2 moles Al2O3. If you need mass, it is 1.2 moles x 102 g/mol = 122 g
How many atoms in a mole of aluminum III oxide?
Aluminium Oxide(Al2O3) has 2 moles of aluminum and 3 moles of oxygen. The total is 5 moles. One mole is 6.022 x 1023 atoms. Therefore, 5 moles = 30.110 x 1023 atoms
