If I understand the question correctly, the answer is 64.
7 x 8 = 56
56.
The number that both 7 and 8 can go into evenly is 56.
To find out how many times one number goes into a second number divide the second number by the first number; In this case 56 ÷ 8 = 7.
7 1/8 57/8 = 56/8 + 1/8 56/8 = 7 (because 7x8=56) :)
How about: 7*8 = 56
7 and 8 if you multiply them. 48 and 8 if you add them. 64 and 8 if you subtract them. 448 and 8 if you divide them.
56
They are: 50+6 = 56 or 7*8 = 56
The number 7 goes into both 56 and 119 (56/7 = 8, 56/7 = 17).
No, but 8 is the GCF of 56 and 72.
There are multiple possible two numbers whose LCM is 56: 1 & 56 2 & 56 4 & 56 7 & 8 7 & 56 8 & 14 8 & 28 8 & 56 14 & 56 28 & 56 56 & 56