(5.72g c6h12o6)*6.022*10^23atoms c6h12o6/180.156gc6h12o6=1.91*10^22 atoms c6h12o6
18 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6.022 X 10^23/1 mole C6H12O6) = 6.02 X 10^22 atoms
The total number of calcium atoms in 80,0 grams of calcium is 12,044 280.10e23.
divide the number of atoms by avogadros number (6.022*10^23), the resulting number is the number of moles you have. Multiply the number of moles of atoms by the molar mass (found on any periodic table) and the answer is how many grams of the substance you have.
The number of carbon atoms is 0,588.10e23.
The mass of silicon is 4 659 g.
The first step is calculating how many molecules of glucose are in 3.00 grams. To do this, you need the molecular mass of the compound (glucose), which is found by adding up the weights of the elements involved in C6H12O6. C6: 12.0 × 6 = 72.0 H12: 1.0 × 12 = 12.0 O6: 16.0 × 6 = 96.0 72.0 + 12.0 + 96.0 = 180.0 grams/mol With this and Avogadro's constant (6.02 × 1023), we can then convert 3.00 grams of glucose to number of molecules. 3.00 grams ÷ 180.0 grams/mol × (6.02 × 1023) = 1.00 × 1022 molecules of glucose So now we know how many molecules of glucose there are. We also know from the formula that in one molecule of glucose, there are 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen. Number of atoms in one molecule × number of molecules = number of atoms in given amount 6 × (1.00 × 1022) = 6.00 × 1022 atoms of carbon 12 × (1.00 × 1022) = 1.20 × 1023 atoms of hydrogen 6 × (1.00 × 1022) = 6.00 × 1022 atoms of oxygen
1.828e25
18 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6.022 X 10^23/1 mole C6H12O6) = 6.02 X 10^22 atoms
Approx 6.01*10^23 atoms.
Approx 1.5*10^23 atoms.
The number of moles is 2,997.
Glucose is 180.16 g/mol. Doing stoichiometry, this means 1.97 grams is 0.0109 mol glucose. Because there are 6 mols of carbon per 1 mol of glucose, that means there are 0.0656 mols of carbon in this sample. One mole is equivalent to 6.023 x 1023 atoms, which leads to 3.95 x 1022 carbon atoms.
glucose 1 mole has 180,156 grams and has 6.022 x 1023 atoms carbon 1 mole has 12,01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72,06 grams out of the 180,156. Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of carbon in one gram of glucose.
To convert grams into atoms, you have to convert them into moles first. Get the molar mass and multiply it by the number of moles to get the atoms.
The total number of calcium atoms in 80,0 grams of calcium is 12,044 280.10e23.
Helium because it has fewer atoms, so there are more atoms needed to have 3.5 grams of it.
It is the sum of the atomic weights of atoms contained in the molecule, expressed in grams.