0.43 moles, since 1 mole of gas occupies 22.4 L at STP.
The answer is 2,5 moles.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
500 of 'em little critters
The number of argon moles is 0,25.
At STP, one moles will occupy 22.4 liters.
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
1 mole of an ideal gas occupies 22.4 liters at STP - so 2 moles occupies 44.8 liters.
The answer is 0,2675 moles.
1 mole of gas = 22.7 litre ( at STP) 22.7 Litre of gas = 1 mole 1 litre of gas = 2.27 litre of gas = mole www.examville.com
The answer is 0,305 moles at 1 at and 25 0C.
22.4L=1 mole of gas at STP
At standard temperature and pressure (STP), 1 mole of any gas occupies about 22.4 liters of space. If you have 3.75L of a gas, then 3.75/22.4=0.17 moles.
Volume is not constant; it is directly related to the number of moles of the gas. (mols gas * 22.4 = volume gas @ STP) Temperature and pressure are constant.
PV = nRT (1atm)(500L) = (n)(0.08206Latm/molK)(298.15K) = 20.4 moles He
The amount of oxygen is 0,067 moles.